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Blizzard [7]
2 years ago
10

Hi, hope you are well, please help me on this (:

Mathematics
1 answer:
valina [46]2 years ago
5 0

Answer:

1. True

2. False

3. True

Step-by-step explanation:

1. (x,y) = (3,1). x = 3; y = 1

2. Vertical is y and horizontal is x

3. The origin is (0,0), The only time these two x and y axis intercept.

You might be interested in
What percent of 30 is 33
Llana [10]
Hi!

To solve this we can set up a proportion and cross multiply.

\frac{33}{30}  \frac{x}{100}

33 x 100 = 3300
3300/30 = 110

The answer is 110%

Hope this helps! :)
3 0
3 years ago
Point I is on line segment HJ. Given I J equals 3X +3, HI equals 3X-1, and HJ equals 3X +8, determine the numerical length of HJ
Nezavi [6.7K]

Answer:

Step-by-step explanation:

3x + 3 + 3x - 1 = 3x + 8

6x + 2 = 3x + 8

3x + 2 = 8

3x = 6

x = 2

HJ= 3(2) + 8 =6 + 8 = 14

HI= 3(2) - 1 = 6 - 1 = 5

IJ = 3(2) + 3 = 6 + 3 = 9

4 0
3 years ago
Read 2 more answers
I need help ON THIS PLS
Anit [1.1K]

Answer:

No, because the ratio of pay to hours is not the same for each pair of value.

8 0
3 years ago
752447 rounded to the nearest hundred thousand
Schach [20]
800,000 is the right answer.
7 0
3 years ago
6. If the net investment function is given by
Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated  capital for the period.

  • (a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.

  • (b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.

Reasons:

(a) The given investment function is presented as follows;

I(t) = 100 \cdot e^{0.1 \cdot t}

(a) The capital formation is given as follows;

\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot  e^{0.1 \cdot t}} + C

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore,  for the three years; Year 3, year 4, and year 5, we have;

\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

\displaystyle  \mathbf{\left[1000 \cdot  e^{0.1 \cdot t}} + C \right]^t_0} = 100,000

Which gives;

\displaystyle 1000 \cdot  e^{0.1 \cdot t}} - 1000 = 100,000

\displaystyle \mathbf{1000 \cdot  e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000

\displaystyle e^{0.1 \cdot t}} = 101

\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15

The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.

Learn more investment function here:

brainly.com/question/25300925

6 0
2 years ago
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