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jeka57 [31]
2 years ago
14

Part B

Mathematics
1 answer:
NARA [144]2 years ago
6 0

Answer:

All of them work.

Step-by-step explanation:

Part D stated any number can be put and the equation will still be the same. I already answered this question for another guy and tou can go search for that if you want to see edmentums sample answer that states they all work.

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A cheetah runs at a speed of 150 kmph. It covers a distance of 750 m in:
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5 0
2 years ago
(1 point) Suppose we want a 95% confidence interval for the average amount spent on books by freshmen in their first year at col
Ne4ueva [31]

Answer:

a) n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

b) For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=16 represent the population standard deviation

n represent the sample size  

Solution to the problem

Part a

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

Part b

For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

5 0
3 years ago
What is the solution set of the equation 3x2 = 48 ?​
nalin [4]

Answer:

Step-by-step explanation:

6=48

6 0
3 years ago
Enter the sum of numbers as a product of their GCF.75 + 90
Semmy [17]
The gcf of the numbers are 15
5 0
2 years ago
I NEED HELP PLSSS<br><br> Find the value of x.
tankabanditka [31]

Answer:

1) x= 43

2) x= 54

Step-by-step explanation:

you add the two angles given, then take that answer and subtract it from 180!

i hope this helped!!

7 0
2 years ago
Read 2 more answers
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