ADP and ABQ are tangents to the circle, centre O.

Which of the following options represents the graph of the function shown below?

grigory [225]

I think the answer is B but not sure about "11" in A

4 0

3 years ago

A coin is tossed 20 times. It lands heads four times. Compare the experimental probability to its theoretical probability. If th

MrRa [10]

Theoretical probability is based on the likelihood of events.

if a coin is flipped 20 times, and it has landed on heads 4 times, theres a 50% chance it would land on heads the 5th time.

it could be that heads gets more than tails or it could be vise versa.

The probability of getting two heads is 1 in 4.

5 0

2 years ago

Mark records his science scores in each monthly assessment over a period of 5 months. In the first assessment he scores 76%. In

Trava [24]

This is the complete question:

Mark records his science scores in each monthly assessment over a period of 5 months. In the first assessment he scores 76%. In the second assessment he scores 73%. After that, his scores keep increasing by 2% in every assessment. Assume that x represents the number of assessments since he starts recording and y represents the scores in each assessment, which of the following describes the situation?

a. a relation only b.

b. neither a function nor a relation

c. a function only

d. both a relation and a function

Answer:

<u><em>d. both a relation and a function</em></u>

Step-by-step explanation:

<em>A relation</em> is any statement, either verbal or mathematical, that connects, interrelates or associates, two or more elements (objects, persons, variables).

The text describes a situation where the scores in the assesments are related to the number of statements since Mark starts recording, hence this is a relation.

<h2>Is this relation a function or not?</h2>

In order for a relation be a function, the association has to be unambiguos. This means that for a given input only one output can exist. If an input can have two or more outputs, then you can not determine which is the output for that input. This is what defines whether a relation is a function or not.

In the situation described in the text, x is the input, i.e. the number of assessments since Mark starts recording the scores. Definetely, the number of assessment is not repeated: there is only one first assessment, only one second assessment, only one third assessment, ... the number of assessment cannot not get repeated. Of course, if the input is not repeated, there is only one output associated to the input (each assessment has just one associated score) and the relation is a function.

3 0

2 years ago

What is the axis of symmetry for f(x) = 2x2 + 4x + 2? (1 point)

yKpoI14uk [10]

For f(x)=ax^2+bx+c
the axis of symmetry is -b/2a

f(x)=2x^2+4x+2
a=2
b=4
-4/(2*2)=-4/4=-1

the axis of symmetry is x=-1

B

7 0

3 years ago

A recent study reported that high school students spend an average of 94 minutes per day texting. Jenna claims that the average

larisa [96]

Answer:

We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.

Step-by-step explanation:

Jenna claims that the average time of texting at her larger high school is greater than 94 minutes per day.

From here we can see that we have to perform a hypothesis test about a sample mean. The null and alternate hypothesis will be:

Null Hypothesis: $\mu \leq 94$

Alternate Hypothesis: $\mu > 94$

Jenna collected data from a sample of 32 students. So, sample size will be:

Sample Size = n = 32

Sample Mean = x = 96.5

Sample Standard Deviation = s = 6.3

We have to perform a hypothesis test, to test Jenna's claim. Since, the value of Population Standard Deviation is unknown and the value of Sample Standard Deviation is known, we will use One Sample t-test in this case.

The formula to calculate the test statistic is:

$t=\frac{x-\mu}{\frac{s}{\sqrt{n}}}$

Using the values, we get:

$t=\frac{96.5-94}{\frac{6.3}{\sqrt{32} } }=2.245$

The degrees of freedom will be:

df = n - 1 = 32 - 1 = 31

We have to convert the t-score 2.245 with 31 degrees of freedom to its equivalent p-value. From t-table this value comes out to be:

p-value = 0.0160

The significance level is:

$\alpha =0.05$

Since, the p-value is lesser than the level of significance, we reject the Null Hypothesis.

Conclusion:

We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.

3 0

3 years ago