ADP and ABQ are tangents to the circle, centre O.

Mathematics

1 answer:

Anarel [89]3 years ago

4 0

Answer:

Step-by-step explanation:

360

You might be interested in

Please help!!!!! Will give brainliest!!

valkas [14]

2.57*10^4 is 1,000,000 times more than 2.57*10^-1

Why?

4-(-1)=5 2

2.57*10^4=25700

2.57*10^-1=0.0257

and

25700

÷ 0.0257

=1000000

and 1000000=10^6

6 0

3 years ago

I really am confused on how to write a proof.

kvasek [131]

Since ABCD is a parallelogram, the opposite sides will be parallel and equal,

$\begin{gathered} AB=CD \\ BC=AD \end{gathered}$

Consider that AC acts as a transversal to the parallel lines AB and CD, so we can write,

$\begin{gathered} \angle CAD=\angle ACB\text{ (Alternate Interior Angles)} \\ BC=AD\text{ (Opposite sides of parallelogram)} \\ \angle ADB=\angle CBD\text{ (Alternate Interior Angles)} \end{gathered}$

So by the ASA criteria, the triangle AED is congruent to the triangle CEB,

Then the corresponding parts of the triangles will be equal,

$\begin{gathered} AE=CE \\ BE=DE \end{gathered}$

Hence Proved.

8 0

1 year ago

What is 8 × 1 + 3 × 0.1 + 9 × 0.01 in standard form

emmasim [6.3K]

Answer:

0.216

Step-by-step explanation:

$8 \times 1 \times 3 \times 0.1 \times 9 \times 0.01\\\\=(8\times1)(3\times0.1)(9\times0.01)\\\\=8(0.3)(0.09)\\\\=(8\times0.3)(0.09)\\\\=(2.4)(0.09)\\\\=2.4\times0.09\\\\=0.216$