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3 years ago

7

Please solve this geometry math problem... I will mark you brainliest

1 answer:

IrinaK [193]3 years ago

5 0

There you go! Hope it helps.

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Answer:

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Step-by-step explanation:

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Pls only do number 13. WILL give brainliest answer

-Dominant- [34]

Answer:

13)

Exact solutions: $\pm \sqrt{7}$

Approximate solutions: $\pm 2.6$

12)

2 is closer to<u> 1.9881</u> than to <u>2.0164</u>, so $\sqrt{2}\approx$ <u> 1.41</u> .

The number line dot should be closer to 1.4 .

Step-by-step explanation:

13) Let $a$ be real positive or zero number.

$x^2=a$ implies $x=\pm \sqrt{a}$ .

You are asked to solve $x^2=7$ .

The solution is $x=\pm \sqrt{7}$ .

Put into calculator to get what $\sqrt{7}$ is approximately.

$\sqrt{7}\approx 2.6$

So the approximate solutions to $x^2=7$ is $\pm 2.6$ .

Basically the inverse operation of squared is square root.

12)

$1.41^2=1.9881$ by calculator.

$1.42^2=2.0164$ by calculator.

$1.43^2=2.0449$ by calculator.

We need to figure out which of the outputs above is closer to 2.

$|2-1.9881|=0.0119$

$|2-2.0164|=0.0164$

$|2-2.0449|=0.0449$

So 2 is closer to 1.9881 which means $\sqrt{2}$ would be closer to $1.41$ .

So anyways let's fill the blanks.

2 is closer to<u> 1.9881</u> than to <u>2.0164</u>, so $\sqrt{2}\approx$ <u> 1.41</u> .

7 0

3 years ago