Answer:
E. 375 degrees to properly bake the pre-risen bagels
The number of mole of carbon dioxide, CO₂ formed from the reaction is 0.0632 mole.
<h3>How to determine the mole of NaHCO₃</h3>
- Molarity of NaHCO₃ = 2 M
- Volume = 31.6 mL = 31.6 / 1000 = 0.0316 M
- Mole of NaHCO₃ =?
Mole = Molarity x Volume
Mole of NaHCO₃ = 2 × 0.0316
Mole of NaHCO₃ = 0.0632 mole
<h3>How to determine the mole of CO₂</h3>
NaHCO₃ + HCl —> CO₂ + H₂O + NaCl
From the balanced equation above,
1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.
Therefore,
0.0632 mole of NaHCO₃ will also react to produce 0.0632 mole of CO₂.
Thus, 0.0632 mole of CO₂ was obtained from the reaction
Learn more about stoichiometry:
brainly.com/question/14735801
We suggest starting to prep for the the SAT as early as eighth grade year. It sound early, but if a student plans on taking the SAT several times throughout high school, eighth graders can take a relaxed and long-view approach to prepping, and can plan on taking their first SAT sophomore year.
I believe the answer is B, I hope that helps!
