Answer: x = 1
Step-by-step explanation:
2log(x+1) - log (x+3) = log 1
log(x+1)^2 - log (x+3) = log 1
log [(x+1)^2 / (x+3)] = log 1
(x+1)^2 / (x+3) = 0
(x+1)^2 = 0
x = 1 or x = -1 (rejected, as log0 does not exist)
Commutative property. :)) Its when 2 numbers are multiplied togther and the product is the same regardless of the order of the 2 numbers.
