Question

Find the equation of the line passing through the points (2, 1) and (5, 10). y= [? ]x + [ ]

Answer 1

Hello There!

y-y1=m(x-x1)

y-1=m(x-2)                       $m=\frac{y2-y1}{x2-x1}$

                                                $m=\frac{10-1}{5-2}$

                                                 $m=\frac{9}{3} \\m=3$

y-1=3(x-2)

y-1=3x-6

y=3x-6+1

y=3x-5

hope it helps

Answer 2

Answer:

y=4x-14

y=4x-14(Y2-Y1)/ (X2-X1) = slope

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.(10-2) (6-4)= 8/2

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.(10-2) (6-4)= 8/2=4

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.(10-2) (6-4)= 8/2=4(4,2)-> choose one point then plug in

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.(10-2) (6-4)= 8/2=4(4,2)-> choose one point then plug in2 = 4(4)+b

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.(10-2) (6-4)= 8/2=4(4,2)-> choose one point then plug in2 = 4(4)+b2 = 16+b

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.(10-2) (6-4)= 8/2=4(4,2)-> choose one point then plug in2 = 4(4)+b2 = 16+bb= -14

y=4x-14(Y2-Y1)/ (X2-X1) = slopey=Mx+b. M= slope B= y-int.(10-2) (6-4)= 8/2=4(4,2)-> choose one point then plug in2 = 4(4)+b2 = 16+bb= -14y= 4x-14

hope that helps wyoo