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3 years ago

(3t^4+4t^3 - 32t² - 5t- 20) (t +4)^-1 show work please

Mathematics

1 answer:

anzhelika [568]3 years ago

8 0

Answer:

3t³-8t²-5

Step-by-step explanation:

(3t4 + 12t³-8t³-32t²-5t-20) x $\frac{1}{t+4}$

(3t³x(t+4)-8t²x(t+4)-5(t+4))x $\frac{1}{t+4}$

(t+4)x(3t³-8t²-5)x $\frac{1}{t+4}$

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