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valina [46]
3 years ago
8

Please help me idk this

Mathematics
1 answer:
pickupchik [31]3 years ago
4 0

Answer:

it would be 2.8150

Step-by-step explanation:

since there is a one in the tenths place it rounds down to 0 with makes it 50

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A radioactive substance has a continuous decay rate of 0.056 per minute. How many grams of a 120 gram sample will remain radioac
sammy [17]

Answer:

The mass of the radioactive sample after 40 minutes is 12.8 g.

Step-by-step explanation:

The mass of the sample can be found by using the exponential decay equation:

N_{t} = N_{0}e^{-\lambda t}

Where:

N(t): is the amount of the sample at time t =?

N₀: is the initial quantity of the sample = 120 g

t = 40 min

λ: is the decay constant =  0.056 min⁻¹

Hence, the mass of the sample after 40 min is:

N_{t} = N_{0}e^{-\lambda t} = 120g*e^{-0.056min^{-1}*40 min} = 12.8 g

     

Therefore, the mass of the radioactive sample after 40 minutes is 12.8 g.

I hope it helps you!

5 0
3 years ago
A sprinter can run 279 feet in 9 seconds. Find the sprinter's unit rate of feet per second.
Lorico [155]
The answer is 31 feet per second :)
4 0
3 years ago
A man watches 9/11 happen with $5.00 in his pocket. How many one dollar bills could he have when The Daily Telegraph began publi
Elan Coil [88]

Answer:

none

Step-by-step explanation:

6 0
3 years ago
The speed that a tsunami can travel is modeled by the equation , where s is the speed in kilometers per hour and d is the averag
dusya [7]

The approximate depth of water for a tsunami traveling at 200 kilometers per hour, given the equation S=356√d, where S is the speed in kilometers per hour and d is the average depth of the water in kilometers, is <u>0.32 km</u>. Hence, <u>option A</u> is the correct choice.

To solve for the average depth of water, when the water is traveling at 200 kilometers per hour, we substitute speed S = 200, in the relation S = 356√d.

This will be solved in the following way:

S = 356√d,

or, 200 = 356√d {Substituting S = 200},

or, 200/356 = (356√d)/356 {Dividing both sides by 356},

or, √d = 0.5618 {Simplifying},

or, d = 0.32 kilometers.

Therefore, the approximate depth of water for a tsunami traveling at 200 kilometers per hour, given the equation S=356√d, where S is the speed in kilometers per hour and d is the average depth of the water in kilometers, is <u>0.32 km</u>. Hence, <u>option A</u> is the correct choice.

The provided question is incomplete.

The complete question is:

"The speed that a tsunami can travel is modeled by the equation S=356√d, where S is the speed in kilometers per hour and d is the average depth of the water in kilometers. What is the approximate depth of water for a tsunami traveling at 200 kilometers per hour?

A. 0.32 km

B. 0.75 km

C. 1.12 km

D. 3.17 km"

Learn more about speed and depth relation at

brainly.com/question/2456082

#SPJ4

5 0
2 years ago
How do you know if a number is prime​
anygoal [31]

Answer:if I only one and that number can go into

Step-by-step explanation:for example 3

5 0
3 years ago
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