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o-na [289]
2 years ago
10

Using the image above, if the density of the LEGO piece is 0.85 g/cm^3, what COULD be a possible measurement for the density of

oil
0.79 g/cm^3

0.8599 g/cm^3

0.95 g/cm^3

1.75 g/cm^3

Mathematics
1 answer:
grin007 [14]2 years ago
6 0

The Lego is submerged under the oil and therefore, is more dense than the oil

The possible density of the oil is the option;

<u>0.79 g/cm³</u>

Reason:

Given:

The density of Lego = 0.85 g/cm³

Density of oil = Required

Solution:

The density of an object is the mass per unit volume it occupies

  • Density = \dfrac{Mass}{Volume}

Increase in density increases the mass a unit volume occupies, therefore, a

more dense object is heavier than a less dense object such that the less

dense object will float on a dense object

The oil is floating on the Lego, therefore, the Lego is more dense than the

oil, and we have;

  • Density of Lego > Density of oil

The density of Lego = 0.85 g/cm³

Therefore;

0.85 g/cm³ > Density of oil

From the given options, the option that has a density less than 0.85 g/cm³ is the the option 0.79 g/cm³

Therefore, the possible density of the oil is <u>0.79 g/cm³</u>

<u />

Learn more here:

brainly.com/question/12864420

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