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vesna_86 [32]
2 years ago
11

Helppppp idk how tu du dis

Mathematics
2 answers:
Arlecino [84]2 years ago
4 0
This expression simplified is 9n^4+8n^3+4
lubasha [3.4K]2 years ago
4 0
9n^4+8n^3+4

answer^^

hopefully that helped some?!!
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What is 1 1/2 mi in feet
Serga [27]

1 1/2 miles in feet is 7920
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2 years ago
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410−x/7 +70=120. please answer fast i will give brainliest
galben [10]
410 - x/7 +70 = 120
410+70-120=x/7
360=x/7
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3 years ago
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Work out: x+3 5x-2 and x=8 <br> A)&gt;<br> B)&lt;<br> C)=
Ilia_Sergeevich [38]
The correct answer is < (B)
8+3 is 11
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3 0
3 years ago
Rachel was an 85 average after four test. what does she need to earn on the next test if she wants to raise her average to exact
irakobra [83]

she took four tests with one more to take totals 5 tests

 88 x 5 = 440

 all her tests need to equal at least 440 to get an 88 average

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4 0
3 years ago
Stereo speakers are manufactured with a probability of 0.100.10 being defective. TwentyTwenty speakers are randomly selected. Le
olga nikolaevna [1]

Answer:

The expected value of X is 2 with a standard deviation of 1.34.

Step-by-step explanation:

For each speaker, there are only two possible outcomes. Either it is defective, or it is not. The probability of a speaker being defective is independent of other speakers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Stereo speakers are manufactured with a probability of 0.1 of being defective

This means that p = 0.1

Twenty speakers are randomly selected.

This means that n = 20

Let the random variable X be defined as the number of defective speakers. Find the expected value and the standard deviation.

E(X) = np = 20*0.1 = 2

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{20*0.1*0.9} = 1.34

The expected value of X is 2 with a standard deviation of 1.34.

6 0
3 years ago
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