Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
6 under par is written as -6
2 over par is written as 2
even par is written as 0
even par is written as 0
Total score: add all the numbers together:
-6 + 2 + 0 + 0 = -4 ( 4 under par).
Answer:
5% but not sure
Step-by-step explanation:
80+5+10
Answer:
B Step-by-step explanation:
Answer:
6 mph
Step-by-step explanation:
Difference in distance
= 15 - 12
= 3 mi
time taken
= 30 mins
= 1/2 hour
Speed
= 3 ÷ 1/2
= 6 mph
