In order to have infinitely many solutions with linear equations/functions, the two equations have to be the same;
In accordance, we can say:
(2p + 7q)x = 4x [1]
(p + 8q)y = 5y [2]
2q - p + 1 = 2 [3]
All we have to do is choose two equations and solve them simultaneously (The simplest ones for what I'm doing and hence the ones I'm going to use are [3] and [2]):
Rearrange in terms of p:
p + 8q = 5 [2]
p = 5 - 8q [2]
p + 2 = 2q + 1 [3]
p = 2q - 1 [3]
Now equate rearranged [2] and [3] and solve for q:
5 - 8q = 2q - 1
10q = 6
q = 6/10 = 3/5 = 0.6
Now, substitute q-value into rearranges equations [2] or [3] to get p:
p = 2(3/5) - 1
p = 6/5 - 1
p = 1/5 = 0.2
Answer:
4/11 of the class did not walk to school.
Step-by-step explanation:
11/11 - 7/11 = 4/11
Weekend just includes Saturdays and Sundays, so you don't have to count the earnings on Friday. You simply have to count the number of hours that passed from 7 am to 11 pm on Saturday. That would be a total of 16 hours. While on Sunday, the time from 9 am to 9 pm is a total of 12 hours. Hence, the total time would be 16 hours + 12 hours = 28 hours
Gross Wage = $20(28 hours) = $560
