Ask question

Ask question

All categories

2 years ago

12

A cricket team gained 10 meters during their game. Express how many meters they gained as an integer What is the opposite of tha

t integer?

1 answer:

REY [17]2 years ago

8 0

Answer:

Step-by-step explanation:

10 and -10

You might be interested in

Susan's art class is 8 hours long. How long is her class in minutes?

PilotLPTM [1.2K]

Answer: 480 minutes

Step-by-step explanation:

8 hours x 60 minutes in a hour = 480

4 0

3 years ago

Read 2 more answers

There are nickels, dimes, quarters in a large piggy bank, for every 2 nickels there are 3 dimes, for every 2 dimes there are 5 q

Alex

There are 80 nickels and 120 dimes and 300 quarters in piggy bank

<em><u>Solution:</u></em>

Given that,

For every 2 nickels there are 3 dimes ,

So, ratio of nickel to dime will be 2 : 3

Also for every 2 dimes there are 5 quarters

So, ratio of dime to quarters is 2 : 5

Let us first find the ratio of nickles to dimes to quarters

nickel : dime = 2 : 3

dime : quarters = 2 : 5

$\frac{nickel}{dime} = \frac{2}{3}$

$nickel = \frac{2}{3} dime$

$\frac{dime}{quarter} = \frac{2}{5}$

$quarter = \frac{5}{2}dime$

So,

$nickel : dime : quarter = \frac{2}{3}dime : dime : \frac{5}{2}dime\\\\nickel : dime : quarter = \frac{2}{3} : 1 : \frac{5}{2}\\\\nickel : dime : quarter = 4 : 6 : 15$

Thus nickel : dime : quarters = 4 : 6 : 15

Now, let the number of nickel be 4x

Let the number of dimes be 6x

Let the number of quarters be 15x

From given question,

There are 500 coins in all.

number of nickel + number of dimes + number of quarters = 500

4x + 6x + 15x = 500

25x = 500

x = 20

Thus,

number of nickel = 4x = 4(20) = 80

number of dimes = 6x = 6(20) = 120

number of quarters = 15x = 15(20) = 300

Thus there are 80 nickels and 120 dimes and 300 quarters in piggy bank

3 0

3 years ago

I need help with f & h I need to see the steps to get the answer, not just the answer.

klemol [59]

24÷1000= 3/125 =0.024(f)

6 0

3 years ago

Find the vertical, horizontal, and slant asymptotes, if any for y=x^3/ (x-2)^4

VashaNatasha [74]

This has both a horizontal and a vertical asymptote. There are no slant (oblique) asymptotes cuz the degree of the numerator is not higher than that of the denominator. If the degree of the numerator is less than the degree of the denominator, which is our case here, then the horizontal asymptote is 0. But we also have a vertical asymptote, which occurs where the denominator = 0. We all know that we break every rule known to mankind if we try to divide by 0, so there also a vertical asymptote at x = 2.

7 0

3 years ago

A rectangle has an area of 75.2m

Degger [83]

Answer:

94.8

Step-by-step explanation:

Aera is : length *width

75.2 = 0.8 * x then x =94

Perimeter is : length + width =94 +0.8

3 0

3 years ago