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Lana71 [14]
3 years ago
8

Find the equation of the line passing through the points (2, -1) and (-6, -5)

Mathematics
1 answer:
timurjin [86]3 years ago
5 0
Answer: The equation that goes through the points (2, -1) and (-6, -5) is 1/2x - 2

I know this because when I graphed this equation, it passed through those points. (My graph is shown below)

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Find magnetic azimuth from stream 89 degrees magnetic azimuth from pond 14degrees
Vera_Pavlovna [14]

Answer:

The Azimuths are 81 degrees, 6 degrees for Grid Azimuths and 269 degrees, 194 degrees for back Azimuths

Step-by-step explanation:

Stream = 89 degrees and Pond = 14 degrees

To Convert to grid Azimuth

G-M Azimuth of 89-8=81 degrees

G-M Azimuth of 14-8=6 degrees

To obtain the back Azimuth for the stream

89+180=269 degrees

To obtain the back Azimuth for the pond

14+180=194 degrees

8 0
3 years ago
1. Use the formula V = Bh to find the volume of a gift box that is 3.5 inches
kaheart [24]

Answer:

147

Step-by-step explanation:

Length x Width = base

Base x Height = Volume

7 0
3 years ago
Raul and Ruth Are saving for a trip.Raul starts with $350 and saves $15 per week.Ruth starts with $200 and saves $25 per week. W
den301095 [7]
Develop two linear equations to represent the savings of these two people:
Raul:  rl=$350 + $15x
Ruth:  rh=$200 + $25x
In both cases, x represents the number of weeks elapsed.

When will these two people have saved up the same amount?  Set rl = rh and solve for x, the number of weeks elapsed:

$350 + $15x = $200 + $25x

$150 = $10x           gives us x= 15.  Their savings will be equal after 15 weeks.
6 0
4 years ago
The owner of a chain of 12 restaurants wants to conduct a survey to determine whether his employees are properly informed by the
goldenfox [79]

Answer: non random and biased. Random and un biased

Step-by-step explanation:

Just answered it

8 0
3 years ago
I need help with this problem from the calculus portion on my ACT prep guide
LenaWriter [7]

Given a series, the ratio test implies finding the following limit:

\lim _{n\to\infty}\lvert\frac{a_{n+1}}{a_n}\rvert=r

If r<1 then the series converges, if r>1 the series diverges and if r=1 the test is inconclusive and we can't assure if the series converges or diverges. So let's see the terms in this limit:

\begin{gathered} a_n=\frac{2^n}{n5^{n+1}} \\ a_{n+1}=\frac{2^{n+1}}{(n+1)5^{n+2}} \end{gathered}

Then the limit is:

\lim _{n\to\infty}\lvert\frac{a_{n+1}}{a_n}\rvert=\lim _{n\to\infty}\lvert\frac{n5^{n+1}}{2^n}\cdot\frac{2^{n+1}}{\mleft(n+1\mright)5^{n+2}}\rvert=\lim _{n\to\infty}\lvert\frac{2^{n+1}}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^{n+1}}{5^{n+2}}\rvert

We can simplify the expressions inside the absolute value:

\begin{gathered} \lim _{n\to\infty}\lvert\frac{2^{n+1}}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^{n+1}}{5^{n+2}}\rvert=\lim _{n\to\infty}\lvert\frac{2^n\cdot2}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^n\cdot5}{5^n\cdot5\cdot5}\rvert \\ \lim _{n\to\infty}\lvert\frac{2^n\cdot2}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^n\cdot5}{5^n\cdot5\cdot5}\rvert=\lim _{n\to\infty}\lvert2\cdot\frac{n}{n+1}\cdot\frac{1}{5}\rvert \\ \lim _{n\to\infty}\lvert2\cdot\frac{n}{n+1}\cdot\frac{1}{5}\rvert=\lim _{n\to\infty}\lvert\frac{2}{5}\cdot\frac{n}{n+1}\rvert \end{gathered}

Since none of the terms inside the absolute value can be negative we can write this with out it:

\lim _{n\to\infty}\lvert\frac{2}{5}\cdot\frac{n}{n+1}\rvert=\lim _{n\to\infty}\frac{2}{5}\cdot\frac{n}{n+1}

Now let's re-writte n/(n+1):

\frac{n}{n+1}=\frac{n}{n\cdot(1+\frac{1}{n})}=\frac{1}{1+\frac{1}{n}}

Then the limit we have to find is:

\lim _{n\to\infty}\frac{2}{5}\cdot\frac{n}{n+1}=\lim _{n\to\infty}\frac{2}{5}\cdot\frac{1}{1+\frac{1}{n}}

Note that the limit of 1/n when n tends to infinite is 0 so we get:

\lim _{n\to\infty}\frac{2}{5}\cdot\frac{1}{1+\frac{1}{n}}=\frac{2}{5}\cdot\frac{1}{1+0}=\frac{2}{5}=0.4

So from the test ratio r=0.4 and the series converges. Then the answer is the second option.

8 0
1 year ago
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