All categories

4 years ago

Simplify square root. BRAINLIEST! Help asap! (For the 2nd one, i accidentally clicked 9 so just act like there is no yellow)

Mathematics

1 answer:

Kazeer [188]4 years ago

3 0

Answer:

$\sqrt{2}\cdot \sqrt{200}=20\\\sqrt{25}+\sqrt{4}=7$

Step-by-step explanation:

$200=2\times100=2\times10\times10\\200=2\times10^2\\\sqrt{200}=\sqrt{2\times10^2}=\sqrt{2}\times\sqrt{10^2} \\=10\sqrt{2} \\\\\sqrt{2}\cdot \sqrt{200}=(\sqrt{2})\cdot(10\sqrt{2})\\=10\cdot(\sqrt{2}\times\sqrt{2})\\=10\cdot2\\=20$

$25=5\times5=5^2\\\sqrt{25}=\sqrt{5^2}=5\\4=2\times2=2^2\\\sqrt{4}=\sqrt{2^2}=2\\\sqrt{25}+\sqrt{4}=5+2=7$

You might be interested in

What are the coordinates of the vertex for y= x + 71 – 2

Alika [10]

All i got is (3,8) (2,5) and (2,-6)

6 0

3 years ago

HELP DUE TOMORROW ASAP BAINLYEST

Tresset [83]

Answer:

B is the correct answer

Step-by-step explanation:

3/12 = 1/4 = 0.25

5 0

3 years ago

Read 2 more answers

How do I solve p=e squared/r when solving for r?

Novay_Z [31]

Answer: $\displaystyle r = \frac{e^2}{p}$

===============================================

Work Shown:

$p = \frac{e^2}{r}\\\\pr = e^2\\\\r = \frac{e^2}{p}\\\\$

Explanation:

In the second step, I multiplied both sides by r to move it to the left side. Then I divided both sides by p to isolate r.

In short, the r and p swap places.

3 0

1 year ago

Answer for brainliest no wrong answers please :)

nadezda [96]

9514 1404 393

Answer:

Step-by-step explanation:

The amount of simple interest is given by ...

I = Prt . . . . . amount P invested at annual rate r for t years

This can be solved for r:

r = I/(Pt)

Using the given values, we find the rate to be ...

r = 16/(200·2) = 16/400 = 4/100 = 4%

The annual interest rate is 4%.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Clarge%7B%5Cbold%20%5Cred%7B%20%5Csum%20%5Climits_%7B8%7D%5E%7B4%7D%20%7Bx%7D%5E%7B2%7D%2

kiruha [24]

Answer:

No solution

Step-by-step explanation:

We have

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

For the sum it is not correct to assume

$\sum_{x=8}^{4}x^2= 8^2 + 7^2+6^2+5^2+4^2 = 64+49+36+25+16 = 190$

Note that for

$\sum_{x=a}^b f(x)$

it is assumed $a\leq x \leq b$ and in your case $\nexists x\in\mathbb{Z}: a\leq x\leq b$ for $a>b$

In fact, considering a set $S$ we have

$\sum_{x=a}^b (S \cup \varnothing) = \sum_{x=a}^b S + \sum_{x=a}^b \varnothing$ that satisfy $S = S \cup \varnothing$

This means that, by definition $\sum_{x=a}^b \varnothing = 0$

Therefore,

$\sum_{x=8}^{4}x^2 = 0$

because the sum is empty.

For

$9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

we have other problems. Actually, this case is really bad.

Note that $\cos^2(\infty)$ has no value. In fact, if we consider for the case

$\lim_{x \to \infty} \cos^2(x)$ , the cosine function oscillates between $[-1, 1]$ , and therefore it is undefined. Thus, we cannot evaluate

$9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

and then

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

has no solution

7 0

3 years ago