Answer: See each one below:
1) Since she is paying for 30% of the cost, we multiply it by 0.3. Then, since it is over the whole year, we divide it by 12.
12304 * 0.3 / 12 = 307.6 B
2) First, we subtract the cost of the 50 deductible, then multiply the amound by 0.2 because he has to pay 20% of the balance.
1060 - 50 = 1010 x 0.2 = 202 A
3) First, we find the total cost of the visits. Mattie has to pay for 40% so times it by 0.4. Then, don't forget to add in the cost of 12 co-pays of $15 each.
3660 * 0.4 = 1464 + 15(12) = 1664 B
Answer: The answer is ![\textup{The other root is }\dfrac{8}{3}~\textup{and}q=40.Step-by-step explanation: The given quadratic equation is[tex]3x^2+7x-q=0\\\\\Rightarrow x^2-\dfrac{7}{3}x-\dfrac{q}{3}=0.](https://tex.z-dn.net/?f=%5Ctextup%7BThe%20other%20root%20is%20%7D%5Cdfrac%7B8%7D%7B3%7D~%5Ctextup%7Band%7Dq%3D40.%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%20%20%3C%2Fstrong%3EThe%20given%20quadratic%20equation%20is%3C%2Fp%3E%3Cp%3E%5Btex%5D3x%5E2%2B7x-q%3D0%5C%5C%5C%5C%5CRightarrow%20x%5E2-%5Cdfrac%7B7%7D%7B3%7Dx-%5Cdfrac%7Bq%7D%7B3%7D%3D0.)
Also given that -5 is one of the roots, we are to find the other root and the value of 'q'.
Let the other root of the equation be 'p'. So, we have
and
Thus, the other root is 
and the value of 'q' is 40.
Noah has 75 marbles. Noah has more marbles. this is because 34 times 3 is equal to 102. since michelle takes 9 marbles from EACH box, 9 times 3 is 27. 102 minus 27 is 75
9514 1404 393
Answer:
the origin
Step-by-step explanation:
Both terms are of odd degree, so the function is an odd function. It is symmetrical with respect to the origin.
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If you recast this as y = f(x), then ...
f(x) = x^(3/5)
When we look at f(-x), we find ...
f(-x) = ((-x)^3)^(1/5) = -(x^3)^(1/5) = -(x^(3/5)) = -f(x)
An odd root of a number has the same sign as the number.
When f(-x) = -f(x), the function is odd and symmetrical about the origin.
The primary reason why scientific notation is important is that it allows us to convert very large or very small numbers into much more manageable sizes. When these numbers are in scientific notation, it is much easier to work with them
