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kobusy [5.1K]
3 years ago
15

You are planning to give you're a regale birthday surprise this coming 12 of July as she about to celebrate her 50th birthday. T

he Venue 88 as place to where the celebration will be held offers you a deal for the venue cost with a base fare of 50,000 pesos plus 100 per guest in excess of 100 guest and your budget for venue expenses is limited only to 150,000.
1. State cost as a function of number of guest.
2. Determine the expression for the inverse.​
Mathematics
1 answer:
velikii [3]3 years ago
3 0

All functions have an inverse expression.

  • The cost function is: \mathbf{C(x) = 40000 + 100x}.
  • The inverse function is: \mathbf{C'(x) = 0.01x - 400 }

From the question, we have the following observations:

  • Base fare = 50000 pesos for first 100
  • Additional guest = 100 pesos

So, the cost function would be:

\mathbf{C(x) = 50000 + (x - 100) \times 100}

Where: x represents the number of guests, and C(x) represents the cost function

Expand

\mathbf{C(x) = 50000 + 100x - 10000}

Evaluate like terms

\mathbf{C(x) = 40000 + 100x}

To calculate the inverse function, we have:

\mathbf{C(x) = 40000 + 100x}

Replace C(x) with y

\mathbf{y = 40000 + 100x}

Swap x and y

\mathbf{x = 40000 + 100y}

Subtract 40000 from both sides

\mathbf{x - 40000 = 100y}

Divide both sides by 100

\mathbf{\frac{x - 40000}{100} = y}

Rewrite as:

\mathbf{y= \frac{x - 40000}{100} }

Split

\mathbf{y= \frac{x}{100} - \frac{40000}{100} }

\mathbf{y= 0.01x - 400 }

Hence, the inverse function is: \mathbf{C'(x) = 0.01x - 400 }

Read more about functions and inverse at:

brainly.com/question/10300045

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3 years ago
A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the
Svetlanka [38]

Answer:

The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be x.

And the hotel charge in second city before tax be y.

<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>

<em>Thus</em>,

y=x-1500   ........(1)

<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>

6% of x + 10% of y = $670.

\frac{6x}{100} +\frac{10y}{100} =670

0.06x+0.10y=670

Substituting the value of y from equation (1) we get:

0.06x+0.10(x-1500)=670

0.06x+0.10x-150=670

0.16x-150=670

<em>Adding both sides by 150 we get:</em>

0.16x=820

<em>Dividing both sides by 0.16 we get:</em>

x=5125.

<em>The hotel charge in first city before tax = $5125.</em>

Now, substituting the value of x in equation (1) we get:

y=x-1500

y=5125-1500

y=3625.

<em>The hotel charge in second city before tax = $3625.</em>

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

5 0
4 years ago
Which list shows the mean, median, mode, and range in ascending order for the set of data below?
Musya8 [376]
15,15,15,19,19,22,23,24,27,30,31,35,41,44,45

the mean (average) can be found by adding up all the numbers and dividing that by how many numbers there are.
The mean of this data set is : 405/15 = 27

the mode is the number that appears most often in ur data set
so the mode is : 15

the range is the highest number - the lowest number
the range is (45 - 15) = 30

the median is ur middle number
the median is : 24

ascending order (smallest to largest) is : mode, median, mean, range
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4 years ago
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