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Greeley [361]
3 years ago
13

What is 0.7 in word form

Mathematics
2 answers:
tamaranim1 [39]3 years ago
5 0
0.7 in word form is : “zero point seven”

Hope this helped <3
kipiarov [429]3 years ago
3 0
Seven tenths. Hope this helps!
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Please help!!! Please help!!! Please help!!!
Elis [28]

Answer:

See explanation.

Step-by-step explanation:

Tyler wrote everything correct, except he multiplied some incorrectly. 2x times 5 is 10x, not 7x. And 3 times 5 is 15, not 8. The bottom left and right boxes are incorrect.

6 0
2 years ago
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Find the quotient.
never [62]

Answer:

48÷3=16

Step-by-step explanation:

In the expression, 96 divided by 8 = a , the quotient a =12

. Divide 12 lizards into 6 equal groups. How many lizards are in each group?

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3 years ago
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Help me on this radical expression !
n200080 [17]

\boxed{pd\sqrt[4]{48p^3d}}

<h2>Explanation:</h2>

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\sqrt[4]{48p^7d^5}

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\sqrt[4]{48p^7d^5} \\ \\ \\ We \ can \ write: \\ \\ p^7=p^4\cdot p^3 \\ \\ d^5=d^4\cdot d \\ \\ \\ So: \\ \\ \sqrt[4]{48p^4\cdot p^3\cdot d^4\cdot d} \\ \\ \\ By \ property: \\ \\ \sqrt[n]{x^n}=x \\ \\ \\ Finally: \\ \\ \boxed{pd\sqrt[4]{48p^3d}}

<h2>Learn more:</h2>

Mathematical expressions: brainly.com/question/14200575#

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3 0
3 years ago
Factor the trinomial: x^2-x-12 x 2 − x − 12
aliya0001 [1]
----------------------------

7 0
3 years ago
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A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e
professor190 [17]

Answer:

\chi^2 =\frac{15-1}{25} 16 =8.96

The degrees of freedom are given by:

df = n-1 = 15-1=14

The p value for this case would be given by:

p_v =P(\chi^2

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

Step-by-step explanation:

Information given

n=15 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =16 represent the sample variance

\sigma^2_0 =25 represent the value that we want to  verify

System of hypothesis

We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 \geq 25

Alternative hypothesis: \sigma^2

The statistic is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And replacing we got:

\chi^2 =\frac{15-1}{25} 16 =8.96

The degrees of freedom are given by:

df = n-1 = 15-1=14

The p value for this case would be given by:

p_v =P(\chi^2

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

6 0
3 years ago
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