<h3>Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.</h3>
<em><u>Solution:</u></em>
Let stamps be s and postcards be p
Given that,
The number of stamps was 4 more than twice the number of postcards
s = 4 + 2p -------- eqn 1
Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28
41 cent = $ 0.41
26 cent = $ 0.26
Therefore,

0.41s + 0.26p = 10.28 --------- eqn 2
Substitute eqn 1 in eqn 2
0.41(4 + 2p) + 0.26p = 10.28
1.64 + 0.82p + 0.26p = 10.28
1.08p = 10.28 - 1.64
1.08p = 8.64
Divide both sides by 1.08
p = 8
Substitute p = 8 in eqn 1
s = 4 + 2(8)
s = 4 + 16
s = 20
Thus Jason bought 20 stamps and 8 post cards
Hi,
A is the answer as : -2+2 = 0 and 5 -5 = 0
Answer:
8x^2 + 5y + 1
Step-by-step explanation:
1 + x^2 - 3 + 2y + 7x^2 + 3 + 3y
group like terms
= x^2 + 7x^2 + 2y + 3y + 1 - 3 + 3
add similar items
= 8x^2 + 2y + 3y + 1 - 3 + 3
add similar items
= 8x^2 + 5y + 1 - 3 + 3
= 8x^2 + 5y + 1
Answer:
C
Step-by-step explanation:
-2 + 7 = 5