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Likurg_2 [28]
2 years ago
14

The number of marbles each sister gets when m marbles are shared equally among four sisters x = m/4

Mathematics
1 answer:
klasskru [66]2 years ago
7 0

Answer:

m/4

Step-by-step explanation:

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For a back to school sale the price of a calculator is reduceded from 70% to $59.50. What is the answer
Leona [35]
Thats what i came up with $25.50
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3 years ago
What is a differential equation
pickupchik [31]
A differential equation is one that contains the derivative of a function.  For example f(x) + 3 = 4f'(x) - 2.  Usually you will be given one of the functions and initial conditions if you have to solve.
5 0
3 years ago
Graph the numbers that are solutions to both inequalities.
nadya68 [22]

Answer:

p ∈ [5 , 6)

Step-by-step explanation:

p + 6 ≥ 11

⇒ p ≥ 11 - 6

⇒ p ≥ 5

⇒ p ∈ [5 , +∞)

3p < 18

⇒ p < 18/3

⇒ p < 6

⇒ p ∈ (-∞ , 6)

Then

p the solution to both equations verify:

p ∈ (-∞ , 6) ∩ [5 , +∞)

Conclusion :

p ∈ [5 , 6)

3 0
1 year ago
PLEASE HELP! I WILL MARK AS BRAINLIEST!! I REALLY NEED SOMEONES HELP!
Andrej [43]

Since this is subtraction, everything must be turned negative in the second polynomial.

(6x^2 - 5x) - (2x^2 + 3x - 2)

6x^2 - 5x - 2x^2 - 3x - (-2)

6x^2 - 5x - 2x^2 - 3x + 2

Now, reorder the terms to make it easier.

6x^2 - 2x^2 - 5x - 3x + 2

Now, just combine like terms.

4x^2 - 5x - 3x + 2

4x^2 - 8x + 2

There’s the answer!

Please consider marking this answer as Brainliest to help me advance.

4 0
3 years ago
What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?
xxMikexx [17]

We have been given an equation of hyperbola \frac{(y+3)^2}{81}-\frac{(x-6)^2}{89}=1. We are asked to find the center of hyperbola.  

We know that standard equation of a vertical hyperbola is in form \frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1, where point (h,k) represents center of hyperbola.

Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.

To find the value of k, we need to rewrite our equation as:

\frac{(y-(-3))^2}{81}-\frac{(x-6)^2}{89}=1

Now we can see that value of k is -3. Therefore, the vertex of given hyperbola will be at point (6,-3) and option D is the correct choice.

6 0
3 years ago
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