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Marianna [84]
3 years ago
6

Shania has started a new job as an app developer. Her first task was to make an old app designed for Android available on other

platforms. Which of the following would make her job easiest and fastest?
A. Develop different versions of the same app for different programs.B. Use cross-platform tools to write code that will translate the existing Android app code into different native formats.C. Feed the existing code into cross-platform tools to develop different versions of the same app.D. Use the same set of codes for different platforms.
Computers and Technology
1 answer:
Fantom [35]3 years ago
8 0

Answer:

B. Use cross-platform tools to write code that will translate the existing Android app code into different native formats.

Explanation:

Cross-platform application development tools are tools that can be used tool generate applications of different platforms, by just writing a single type of code. It has the ability to automatically create an application of a different platform from another.

A developer can develop an application like Android and convert it to IOS for Apple. Xamarin, Appcelerator coroner etc, are all examples of cross-platform tools.

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All of these have todo with style

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2 years ago
Write a class called Course that represents a course taken at a school. Represent each student using the modified Student class
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Answer:

The code is given below with its appropriate output

Explanation:

//Student.java

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class Student {

public String firstName;

public String lastName;

public float[] marks;

Scanner scanner = new Scanner(System.in);

public Student(String firstName, String lastName) {

this.firstName = firstName;

this.lastName = lastName;

}

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mark = scanner.nextFloat();

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else {

System.out.println("you entered mark is invalid");

marks[i] = 0;

}

} else

System.out.println(" maximum is five only");

}

}

public void tostring() {

System.out.println("firstname :" + "\t" + firstName + "\t" + "lastname :"

+ "\t" + lastName + "\n" + "the marks are");

int count = 0;

for (float mark : marks) {

count++;

System.out.println("the mark of " + count + " is " + mark);

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}

public void Averagecal() {

float sum = 0.0f;

for (float mark : marks) {

sum = sum + mark;

}

float avg = sum / 5;

System.out.println("average of a student is " + avg);

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}

//Course.java

import java.io.*;

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class Course {

public String courseName;

public int number;

Student[] students;

Scanner scanner = new Scanner(System.in);

public Course(String courseName) {

this.courseName = courseName;

}

public void addStudents() {

System.out

.println("how many no of students you want to add for this particular course");

int count = scanner.nextInt();

students = new Student[count];

for (int i = 0; i < count; i++) {

System.out.println("enter the first name");

String fname = scanner.next();

System.out.println("enter the last name");

String lname = scanner.next();

Student s = new Student(fname, lname);

s.getdetail();

s.tostring();

s.Averagecal();

students[i] = s;

}

}

public void roll() {

int count = 0;

for (Student stud : students) {

count++;

}

System.out.println("the no of students in this " + courseName

+ " course is " + count);

}

}

//Driver.java

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class Driver {

public static void main(String[] args) {

Course course = new Course("java");

course.addStudents();

course.roll();

}

}

<u>output: </u>

C:\Users\Daniel\Desktop\New folder>javac Student.java

C:\Users\Danie;\Desktop\New folder>javac Course.java

C:\Users\Daniel\Desktop\New folder>javac Driver.java

C:\Users\Daniel\Desktop\New folder>java Driver

how many no of students you want to add for this particular course ?

1

enter the first name

john

enter the last name

rich

enter only five marks

enter score 1

89

enter score 2

91

enter score 3

85

enter score 4

78

enter score 5

96

firstname : john lastname : rich

the marks are

the mark of 1 is 89.0

the mark of 2 is 91.0

the mark of 3 is 85.0

the mark of 4 is 78.0

the mark of 5 is 96.0

average of a student is 87.8

the no of students in this java course is 1

C:\Users\Ravi\Desktop\New folder>

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Answer:

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