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gogolik [260]
3 years ago
10

What number is the opposite of 55

Mathematics
2 answers:
lukranit [14]3 years ago
6 0

Answer:

55

The opposite of 55 is −55.

mixas84 [53]3 years ago
3 0

Answer:

−55

Step-by-step explanation:

The opposite of 55 is −55.

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What is the volume of the prism? (Easy ig)
motikmotik

Answer:

Volume = 42 in.²

Step-by-step explanation:

Volume of the triangular prism = ½×b×h×l

where,

b = 4 in.

h = 3 in.

l = 7 in.

Plug in the values

Volume = ½ × 4 × 3 × 7

Volume = 42 in.³

6 0
3 years ago
Evaluate each expression if: k = 2, m = 7, n = 4.<br> 1) 6m - 3k 2)<br> 23) m + |2m - kl
guapka [62]
6m-3k²
= 6(7) - 3 (2)²
= 42 - 3(4)
= 42 - 12
= 30

m + | 2m-k|

7 + | 2(7) - 2|

7 + | 14-2|

7 + 12

= 19
7 0
3 years ago
If y varies directly as x and y=12 when x=c what is y in terms of c when x=8
tatiyna

"y varies directly as x" means y = kx

you do not know what k is yet, other than that it is some constant number.

Now plug in the given values, y=12 when x=4, in the equation

12 = 4k

=> k = 3

Now rewrite the equation with the k value you just found

y = 3k

Substitute 18 in place of x

y = 3(18)

y = 54

8 0
3 years ago
Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,
vichka [17]

Answer:

A(-1,0) is a local maximum point.

B(-1,0)  is a saddle point

C(3,0)  is a saddle point

D(3,2) is a local minimum point.

Step-by-step explanation:

The given function is  

f(x,y)=x^3+y^3-3x^2-3y^2-9x

The first partial derivative with respect to x is  

f_x=3x^2-6x-9

The first partial derivative with respect to y is  

f_y=3y^2-6y

We now set each equation to zero to obtain the system of equations;

3x^2-6x-9=0

3y^2-6y=0

Solving the two equations simultaneously, gives;

x=-1,x=3  and y=0,y=2

The critical points are

A(-1,0), B(-1,2),C(3,0),and D(3,2).

Now, we need to calculate the discriminant,

D=f_{xx}(x,y)f_{yy}(x,y)-(f_{xy}(x,y))^2

But, we would have to calculate the second partial derivatives first.

f_{xx}=6x-6

f_{yy}=6y-6

f_{xy}=0

\Rightarrow D=(6x-6)(6y-6)-0^2

\Rightarrow D=(6x-6)(6y-6)

At A(-1,0),

D=(6(-1)-6)(6(0)-6)=72\:>\:0 and f_{xx}=6(-1)-6=-18\:

Hence A(-1,0) is a local maximum point.

See graph

At B(-1,2);

D=(6(-1)-6)(6(2)-6)=-72\:

Hence, B(-1,0) is neither a local maximum or a local minimum point.

This is a saddle point.

At C(3,0)

D=(6(3)-6)(6(0)-6)=-72\:

Hence, C(3,0) is neither a local minimum or maximum point. It is a saddle point.

At D(3,2),

D=(6(3)-6)(6(2)-6)=72\:>\:0 and f_{xx}=6(3)-6=12\:>\:0

Hence D(3,2) is a local minimum point.

See graph in attachment.

3 0
3 years ago
It might be D but i dont know
FrozenT [24]

Answer:

I'm sorry I don't have answer but.

it's not C!

8 0
2 years ago
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