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guajiro [1.7K]
3 years ago
15

(ii)

Mathematics
1 answer:
Likurg_2 [28]3 years ago
6 0

Answer:

a₁ = 42

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₅₀ = 140 and a₅₁ = 142 , then

a₁ + 49d = 140 → (1)

a₁ + 50d = 142 → (2)

Subtract (1) from (2) term by term to eliminate a₁

0 + d = 2

d = 2

Substitute d = 2 into (1)

a₁ + 49(2) = 140

a₁ + 98 = 140 ( subtract 98 from both sides )

a₁ = 42

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Answer:

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Step-by-step explanation:

Solve for x:

(4 x)/5 + 4/3 = 2 x

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12 x + 20 = 30 x

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(20 - 20) - 18 x = -20

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(-18)/(-18) = 1:

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x = (-10)/(-9)

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I=PRT
I=interest
P=principal
R=rate in decimal
T=time in years

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Read 2 more answers
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