When we are given a system of 3 linear equations, with 3 variables, we proceed as follows:
We consider 2 pairs or equations, for example (1, 2) and (2, 3), and eliminate one of the variables in each pair, creating a system of 2 linear equations with 2 unknowns.
Note that the third equation contains -2y which can be used to eliminate easily -6y in the second equation, and -4y in the fourth.
i) consider equations 1 and 3:
-3x-4y-3z=-7
5x-2y+5z=9
multiply the second equation by -2:
-3x-4y-3z=-7
-10x+4y-10z=-18
adding the 2 equations we have -13x-13z=-25
ii) consider equations 2 and 3. Multiply the third equation by -3:
2x-6y+2z=3
-15x+6y-15z=-27
adding the 2 equations we have -13x-13z=-24
So we got -13x-13z is -25, but also -24. this means the system is inconsistent, so it has no solution.
Answer: the system has no solutions
The answer would be 9 you would add the 13 and 7 then have 20-5t=-25 then subtract 20 from 25 then you would have -5=-45 which is 9
Answer: a.
a. PROPOSITION ONE is true and PROPOSITION TWO is true
b. PROPOSITION ONE is true and PROPOSITION TWO is false
c. PROPOSITION ONE is false and PROPOSITION TWO is true
d. PROPOSITION ONE is false and PROPOSITION TWO is false
e. None of the above
The slope is -4.7 because this equation is written in point slope form. This equation can be rewritten as y = -4.7x + 21. Point slope form is y = mx + b, with m being slope and b being y-intercept.