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allochka39001 [22]
3 years ago
6

What is the base? Area= 9/10 Height=3/5 PLEASE HELP ME!!

Mathematics
1 answer:
Phantasy [73]3 years ago
8 0
AREA= 1/2 BASE * HEIGHT
9/10 = 1/2x*3/5
x= 9/10*10
x=9
Thus, the base is 9
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-2 ×^2 - 4y +6. x=-3. y=-2 <br> evaluate ​
gladu [14]

Answer:

<u><em>Answer is below</em></u>

Step-by-step explanation:

<em><u>-2 ×^2 - 4y +6</u></em>

<em><u>Evaluate simply means to form an idea of something</u></em>

<em><u>So Evaluate for x=−3,y=−2</u></em>

<em><u>−2(−3)2−(4)(−2)+6</u></em>

<em><u>−2(−3)2−(4)(−2)+6</u></em>

<em><u>Answer =−4</u></em>

8 0
3 years ago
Solve equation and write reason for each step x+25=45
alexdok [17]

just do 45-25= x

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4 0
3 years ago
Read 2 more answers
The vertices of xyz are x (1,-4)
dexar [7]

Answer:

5. The vertices of ΔX'Y'Z' are (-3, -7), (-6, -4), (-1, -2)

6. The vertices of ΔX'Y'Z' are (6, -7), (3, -4), (8, -2)

Step-by-step explanation:

If the point (x, y) translated by T → (h, k), then its image is (x + h, y + k)

#5

In ΔXYZ

∵ X = (1, -4), Y = (-2, -1), Z = (3, 1)

∵ T → (-4, -3)

∴ h = -4 and k = -3

→ Use the rule above to find the image of the vertices of the Δ

∵ X' = (1 + -4, -4 + -3)

∴ X' = (-3, -7)

∵ Y' = (-2 + -4, -1 + -3)

∴ Y' = (-6, -4)

∵ Z' = (3 + -4, 1 + -3)

∴ Z' = (-1, -2)

∴ The vertices of ΔX'Y'Z' are (-3, -7), (-6, -4), (-1, -2)

#6

In ΔXYZ

∵ X = (1, -4), Y = (-2, -1), Z = (3, 1)

∵ T → (5, -3)

∴ h = 5 and k = -3

→ Use the rule above to find the image of the vertices of the Δ

∵ X' = (1 + 5, -4 + -3)

∴ X' = (6, -7)

∵ Y' = (-2 + 5, -1 + -3)

∴ Y' = (3, -4)

∵ Z' = (3 + 5, 1 + -3)

∴ Z' = (8, -2)

∴ The vertices of ΔX'Y'Z' are (6, -7), (3, -4), (8, -2)

6 0
3 years ago
Which number is in scientific notation
I am Lyosha [343]
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6 0
3 years ago
Order from least to greatest: 7.49, 7 49/50, 7.5
stepan [7]
The answer is 7.49, 7.5, 7 49/50
8 0
3 years ago
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