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krek1111 [17]
2 years ago
15

At what rate would you need to invest $12000 and make $2880 after 8 years?

Mathematics
1 answer:
Nady [450]2 years ago
5 0

Answer:

Step-by-step explanation:

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Find the output, k, when the input, t, is –7.<br> k = 10t -19
kupik [55]

Answer:

k = - 89

Step-by-step explanation:

To calculate the output, substitute t = - 7 into the equation for output, that is

k = 10(- 7) - 19 = - 70 - 19 = - 89

7 0
3 years ago
I WILL MAKE YOU BRAINLIEST
34kurt

Answer:

40

Step-by-step explanation:

32/4=8

8 is 2x 4 so multiply 5x2=10

now multiply 10x4

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3 years ago
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The coordinates of the vertices of △JKL are J(1, 4) , K(6, 4) , and L(1, 1) .
gayaneshka [121]
Translation 1 unit left and rotation of 90 degrees counterclockwise
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3 years ago
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Explain how to estimate the quotient using compatible numbers. 27 and two-thirds divided by 3 and StartFraction 9 over 10 EndFra
sladkih [1.3K]

Answer:

The first fraction is between 27 and 28, closer to 28. The second fraction is between 3 and 4, closer to 4. Compatible numbers in division are numbers that can be divided mentally. 28 divided by 4 is 7. The quotient will be around 7.

Step-by-step explanation:

4 0
3 years ago
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The annual tuition at a specific college was $20,500 in 2000, and $45,4120
nika2105 [10]

Answer: the tuition in 2020 is $502300

Step-by-step explanation:

The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = $20500

The fee in 2018 is the 19th term of the sequence. Therefore,

T19 = $45,4120

n = 19

Therefore,

454120 = 20500 + (19 - 1) d

454120 - 20500 = 19d

18d = 433620

d = 24090

Therefore, an

equation that can be used to find the tuition y for x years after 2000 is

y = 20500 + 24090(x - 1)

Therefore, at 2020,

n = 21

y = 20500 + 24090(21 - 1)

y = 20500 + 481800

y = $502300

6 0
3 years ago
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