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krek1111 [17]
3 years ago
15

At what rate would you need to invest $12000 and make $2880 after 8 years?

Mathematics
1 answer:
Nady [450]3 years ago
5 0

Answer:

Step-by-step explanation:

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During a film festival, the first film ticket is priced at $16, and each additional ticket is $11. If Rico spends $71, then how
Nina [5.8K]

Answer:

5

Step-by-step explanation:

16 + 11x = 71

16 + -16 + 11x = 71 + -16

16 + -16 = 0

0 + 11x = 71 + -16

11x = 71 + -16

11x = 55

x = 5

6 0
3 years ago
Algebraic expression the price h of a house plus 10% property tax
zhannawk [14.2K]

Generally we pay h to purchase the house, and then each year must pay 10% of the value of the house in property taxes. We could write:

House owning costs = h + 0.10h = 1.10h.

Note that we'd not likely have to pay a tax on the property when you purchase it, except for relatively small fees such as "transfer tax."


6 0
3 years ago
Proceed with caution Really hard question.
viva [34]

factor out the x+1 from the numerator and denominator to get \frac{1}{x^2 - x}

denominator: x³ - x = x(x² - 1) x(x-1)(x+1)

Answer: J

4 0
3 years ago
The data represent the results for a test for a certain disease. Assume one individual from the group is randomly selected. Find
sertanlavr [38]

Answer:

The probability of getting someone who tests positive​, given that he or she had the disease is 0.8954.

Step-by-step explanation:

The data provided is:

                  YES        NO    Total

Positive      137           8      145

Negative     16          139    155

Total            153         147    300

An individual is selected at random from the group.

We need to compute the probability of getting someone who tests positive​, given that he or she had the disease.

The conditional probability of an event <em>A</em> given that another event <em>B</em> has already occurred is:

P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{n(A\cap B)}{n(B)}

Let <em>A</em> = individuals who tests positive and <em>B</em> = individual who had the disease.

The number of individuals who tests positive and had the disease is,

n (A ∩ B) = 137

n (B) = 153

Compute the conditional probability of A given B as follows:

P(A|B)=\frac{n(A\cap B)}{n(B)}

            =\frac{137}{153}

            =0.8954

Thus, the probability of getting someone who tests positive​, given that he or she had the disease is 0.8954.

8 0
3 years ago
Find the circumference use 3.14 for pie
Vilka [71]

Answer:

31.4 is the answer......

4 0
3 years ago
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