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crimeas [40]
3 years ago
9

The table below represents a linear function f(x) and the equation represents a function g(x):

Mathematics
1 answer:
9966 [12]3 years ago
8 0

Answer:

<u>Use 2 points from he table to find the slope of f(x):</u>

  • (0, -1) and (1, 7)

<u>The slope is:</u>

  • m = (7 - (-1))/1 = 8

The y - intercept is b = -1 according to point (0, -1).

<h3>Part A</h3>

<u>The lines are:</u>

  • f(x) = 8x - 1
  • g(x) = 3x - 2

The f(x) has greater slope since 8 > 3 and greater y-intercept since -1 > - 2.

<h3>Part B</h3>

See above

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Factor 28+56t+28w28+56t+28w28, plus, 56, t, plus, 28, w to identify the equivalent expressions. Choose 2 answers:
Effectus [21]

Answer: The factorization of  28+56t+28w =28(1+2t+w)

The factors of 28+56t+28w are 28 and 1+2t+w.

Step-by-step explanation:

The given expression : 28+56t+28w

To factorize it, we need to find the common factor.

As 56 can be written as 2 x 28.

So, the above expression would become

28+2\times28t+28w

Now, taking 28 as common from all the terms, we will get

28(1+2t+w)

Thus, the factorization of  28+56t+28w =28(1+2t+w)

And the factors of  28+56t+28w are 28 and 1+2t+w.

6 0
3 years ago
Which decimal is equivalent to 8.100
larisa86 [58]

Answer:

81/10

Step-by-step explanation:

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7 0
3 years ago
Jonah recorded the points his team scored during its last nine basketball
Ainat [17]

Jonah recorded the points his team scored during its last nine basketball

games. The mean number of points scored was 42 and the MAD Was 4.4.

The MAD shows that the scores generally varied greatly from the mean.

The scores were mostly less than

38 (42 -4.4 = 37.6)

greater than

46 (42 + 4.4 = 46.4).

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5 0
2 years ago
1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)
Sveta_85 [38]

Answer:

1. -5x+3y+44=0

2. 2x+y-2=0

3. 2x+y-4=0

Step-by-step explanation:

Standard form of a line is Ax+By+C=0.

If a line passing through two points then the equation of line is

y-y_1=m(x-x_1)

where, m is slope, i.e.,m=\dfrac{y_2-y_1}{x_2-x_1}.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)

y+3=\dfrac{-5}{-3}(x-7)

y+3=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

-5x+3y+9+35=0

-5x+3y+44=0

Therefore, the required equation is -5x+3y+44=0.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

Slope of the line : m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

y-2=-2(x-0)

y-2=-2x

2x+y-2=0

Therefore, the required equation is 2x+y-2=0.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y =-5.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

y-0=-2(x-2)

y=-2x+4

2x+y-4=0

Therefore, the required equation is 2x+y-4=0.

5 0
3 years ago
Pls show me how u did it
eduard

Answer:

(2,1)

Step-by-step explanation:

This is because when you type the equations into desmos, this is the cordinate that they collide.

Hope this answers your question.

7 0
2 years ago
Read 2 more answers
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