In this exercise we have to use the knowledge of geometric progression to find three specific numbers, in this way we can say that these numbers correspond to;
Then using the formula of the geometric progression we find that:
now, the differences between the terms must be the same:
and now, when we increase the third term by 9,so we have:
Now we use that identity in the first equation :
The general solution for a quadratic equation is
We have that:
so, put the numbers in the formula we find:
See more about geometric progress at brainly.com/question/14320920
You are given the unknown number which has a quotient of 3 and a
remainder of 28. This means that 3 is the whole number from the division of the
unknown number and 43 and 28 is the decimal, 3.28. Also, the number is divided
by 43 too. Let us denote n as the number so we have n/43. Then equate the n/43
to 3.28.
n/43 = 3.28
n = 43 (3.28)
n = 141.04
<span>The number is 141. 04</span>
Answer:
-1 17/25
Solution with Steps
−65−1225=?
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(-6/5, 12/25) = 25
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
(−65×55)−(1225×11)=?
Complete the multiplication and the equation becomes
−3025−1225=?
The two fractions now have like denominators so you can subtract the numerators.
Then:
−30−1225=−4225
This fraction cannot be reduced.
The fraction
−4225
is the same as
−42÷25
Convert to a mixed number using
long division for -42 ÷ 25 = -1R17, so
−4225=−11725
Therefore:
−65−1225=−11725
Answer:idk 3
Step-by-step explanation: