In June, a runner ran a mile in 7:45. In September, the runner ran a mile in 5:51.

Round the following 8.388 to 2 decimal places

Roman55 [17]

The answer will be 8.39 because the third number (8) is above 5 so you have to round up. Good luck!

3 0

3 years ago

Greatest common factors 4,8 Can u do a factor tree I need help with it

solong [7]

4. 8
/ \ / \
2 x 2. 4 x 2
/ \
2 x 2

4: 2x2
8: 2x2x2

The GCF is 4

7 0

4 years ago

the times that gym members spend on a treadmill are normally distributed with a mean of 20 min and a standard deviation of 8 min

Papessa [141]

Given:
xbar = 20 min
standard deviation = 8 min
total sample = 240

Required:
how many gym members are expected to spend 4 min and 36 min on a treadmill today

Solution:
sd² = (∑(x - xbar)²) / N - 1

there are 42 gym members at 4 minutes and 200 gym members in 36 minutes.

6 0

3 years ago

Is the mean age at which American children learn to walk less than 15 months? A study of 40 American children found a mean walki

Sonbull [250]

Answer:

We define the random variable X as the walking age and we are interested if American children learn to walk less than 15 months so then that would be the alternative hypothesis and the complement would be the null hypothesis.

Null hypothesis: $\mu \geq 15$

Alternative hypothesis: $\mu$

And for this case the best answer would be:

H 0 : μ ≥ 15 vs. Ha : μ < 15

Step-by-step explanation:

We define the random variable X as the walking age and we are interested if American children learn to walk less than 15 months so then that would be the alternative hypothesis and the complement would be the null hypothesis.

Null hypothesis: $\mu \geq 15$

Alternative hypothesis: $\mu$

And for this case the best answer would be:

H 0 : μ ≥ 15 vs. Ha : μ < 15

And the data given from the sample is:

$\bar X = 13.2$ represent the sample mean