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3 years ago

Which expression is equivalent to (2 Superscript one-half Baseline times 2 Superscript three-fourths Baseline) squared?

Mathematics

2 answers:

lozanna [386]3 years ago

8 0

Answer: It’s D

Step-by-step explanation:

On edge

Yuliya22 [10]3 years ago

3 0

Answer:

Your answer is correct

Step-by-step explanation:

(2^5/4)² = 4^5/2 = √4^5

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WILL MARK BRAINLIEST<br>solve for x: m(2m-x)=3(x+6) if m≠3

Lera25 [3.4K]

Answer:

x=2m−6

Step-by-step explanation:

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3 years ago

1. The gaming company whose console received the video game market in 1985 was.

asambeis [7]

1. Nintendo
2. A. True
3. A. Oscilloscope

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3 years ago

What is the volume of this pyramid? 945 cm³ 1260 cm³ 1890 cm³ 2520 cm³ A pyramid with a right triangular base. The right triangu

notsponge [240]

Answer:

The volume of the pyramid is $1,260\ cm^{3}$

Step-by-step explanation:

we know that

The volume of the triangular pyramid is equal to

$V=\frac{1}{3}BH$

where

B is the area of the triangular base

H is the height of the pyramid

step 1

Find the area of the base B

$B=\frac{1}{2}bh$

we have

$b=14\ cm$

$h=18\ cm$

substitute

$B=\frac{1}{2}(14)(18)=126\ cm^{2}$

step 2

Find the volume

we have

$B=126\ cm^{2}$

$H=30\ cm$

substitute

$V=\frac{1}{3}BH$

$V=\frac{1}{3}(126)(30)=1,260\ cm^{3}$

5 0

3 years ago

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How do you find y in the rectangle??

expeople1 [14]

34 divided by 14 is 2.42......
Then multiply it by 6 to get your Y.
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8 0

3 years ago

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

3 0

3 years ago

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