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horsena [70]
3 years ago
8

Let f(x) = x^3 + 2x^2 + 3x + 1 and g(x)= 4x-5 Find f(x) x g(x)

Mathematics
1 answer:
Brums [2.3K]3 years ago
8 0

▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪

Given :

f(x) =  {x}^{3}  + 2 {x}^{2}  + 3x + 1

g(x) = 4x - 5

let's solve for f(x) × g(x) :

( {x}^{3}  + 2x {}^{2}  + 3x + 1)(4x - 5)

4x {}^{4}  - 5 {x}^{3}  + 8 {x}^{3  }  - 10 {x}^{2}  + 12 {x}^{2}  - 15x + 4x - 5

4 {x}^{4}  + 3 {x}^{3}  + 2 {x}^{2}   - 11x - 5

therefore, correct choice is : D

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Answer:

253cm²

Step-by-step explanation:

Area of the trapezoid = 1/2(b1+b2)*h

Given

h = 22cm

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Substitute

Area of the trapezoid = 1/2(10.5+12.5)*22

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tinyurl.com/wpazsebu

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3 years ago
A parcel delivery service will deliver a package only if the length plus girth (distance around) does not exceed 84 in. What are
Lesechka [4]

Answer:

a) \frac{28}{\pi} in

b) 28 in

c) 784 in²

Step-by-step explanation:

Let the length be 'L'

and the radius be 'r'

Thus, according to the question

L + 2πr = 84 in

L = 84 - 2πr   ............(1)

Volume of the cylinder, V = πr²L

substituting the value of L from 1, we get

V =  πr²(84 - 2πr)

or

V = 84πr² - 2π²r³

for points of maxima, differentiating the above equation and equating it to zero

\frac{dV}{dr}=\frac{d(84\pi r^2-2\pi^2 r^3))}{dr}

or

2(84)πr - 3(2)π²r² = 0

or

2πr(84 - 3πr) = 0

or

r = 0    and    84 - 3πr = 0

or

⇒ 3πr = 84

or

⇒ r = \frac{28}{\pi} in

since, the radius cannot be zero therefore, r = 0 is neglected

Therefore,

a) The radius of the largest cylindrical package = \frac{28}{\pi} in

b) from  (2)

L = 84 - 2πr

or

⇒ L = 84 - 2\pi\times\frac{28}{\pi}

or

⇒ L = 84 - 56 = 28 in

The length of the largest cylindrical package = 28 in

c ) The volume of the largest cylindrical package ,V = πr²L

= \pi\times\frac{28}{\pi}\times28

= 784 in²

7 0
3 years ago
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