Answer:
the answer is 34.75
Step-by-step explanation:
first, you take all 4 values and add them up. (you should get 122.)
second, you take the 122 and divide it bye the amount of values. in this case there are 4 (100,4,12, and 6). you will get 30.5. (the mean)
third, take all 4 values and subtract them by 30.5. (100-30.5__4-30.5__12-30.5__6-30.5) you will get negitives just drop the negitive signs and change them to positves.
last, add the distant values together (you should get 139) and divide it by 4 ( you should get 34.75)
Distribute
5x-10=20+2x
minus 2x both sides
3x-10=20
add 10 both sides
3x=30
divide both sides by 3
x=10
We have been given that the test scores on a final exam are normally distributed with a mean of 74 and a standard deviation of 3. We are asked to find the probability that a randomly selected test has a score higher than 77.
First of all, we will find z-score corresponding to sample score 77.
, where,
z = z-score,
x = Random sample score,
= Mean,
= Standard deviation.
Now we need to find .
We will use formula to find the probability greater than a z-score of 1.
Using normal distribution table, we will get:
Therefore, the probability that a randomly selected test has a score higher than 77 would be 0.15866.
The correct answer is number line B.
Explanation:
We are given the inequality x >= -7, that means we have to represent on a number line all numbers that are greater than -7, including -7. that is correctly represented on the number line B, because the black full dot means that -7 is included and the direction of the line goes in the way which is greater than -7.
Hope this helps!