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3 years ago

Me.Ramirez divid 12 frogs

Mathematics

1 answer:

ivanzaharov [21]3 years ago

7 0

Answer: my last names Ramirez!

Step-by-step explanation:

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I need help in geomtry please help

Arada [10]

What exactly is your question?

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4 years ago

What is the value of x?

a_sh-v [17]

In my knowledge

x = 24²+7²

= 576+49= 625

x= sqroot of 625

x = 25 (By Pythagoras Theorem)

Hope it helps

3 0

3 years ago

7+a+8+a= pls help pls help

Alina [70]

Answer:

15+2a

Step-by-step explanation:

7+a+8+a=15+2a

7 0

3 years ago

Boden's account has a principal of $700 and a simple

pashok25 [27]

Answer:

823.2

Step-by-step explanation:

Interest = 700 × 4.4/100 × 4 = 123.2

Balance = Principle + interest

700 + 123.2 = 823.2

Answer - 823.2

Hope this helps!!!

3 0

3 years ago

A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?

VladimirAG [237]

Answer:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

4 0

3 years ago