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pashok25 [27]
3 years ago
8

Which letter on this number line is at -2.25?

Mathematics
1 answer:
svlad2 [7]3 years ago
7 0

Answer:

A.

Step-by-step explanation:

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Solve for x.<br> -7 &gt; 13 - 50<br> Enter your answer as an inequa
Svet_ta [14]
-7>-63 because the more negative the number the less the value
6 0
3 years ago
Translate the sentence into an equation. Four less than a number is 17. Which equation is correct?
lana [24]
Your answer would be x-4=17.
4 less than (#) is 17.

That number would be 21.

21-4=17

Hope that helps
6 0
3 years ago
Surface area of 18 12 and 4 plz help!
Liula [17]
You would start off by finding the base, which is 18*12. That equals 216 meters squared, you multiply that by 2 to get the surface area of your 2 bases. That equals 432 meters squared.  To find the surface area of the sides (on the left and right side), you would use the equation length times height.  To plug in the numbers, you use 12*4, that is 48 meters squared. There are 2 sides, so multiply by 2, to get 96 meters squared.  To find the last side, you take length times width, plug in the numbers. Those numbers are 4*18, which equals 72 meters squared. Once again, there are two sides, so you multiply by 2, to get 144 meters squared.  Next, as the final step, you add up all of the final numbers. They are: 432+96+144 which equals 672 meters squared. 

Your final answer is 672 meters squared.

I hope this helps!
5 0
3 years ago
Find the value of the marked angles in each of the following ( see image ).
brilliants [131]

Answer:

(180-62)

118

180-118=62

180-85=95

180-(62+95)

180-157

23

5 0
3 years ago
Read 2 more answers
Law of sines?? side c=22 side a=16 side b= 21 solve for angle c??? help
den301095 [7]

Answer:

Angle C measures:  71.52^o

Step-by-step explanation:

When you know the length of the three sides of the triangle and not a single angle, the law of sines is of no use. You need to use the law of cosines. In your case, since you want to find angle "C", you use the following;

c^2=a^2+b^2-2\,a\,b\,cos(C)\\2\,a\,b\,cos(C)=a^2+b^2-c^2\\cos(C)=\frac{a^2+b^2-c^2}{2\,a\,b} \\cos(C)=\frac{16^2+21^2-22^2}{2\,(16)\,(21)}\\cos(C)=0.3169643\\C=arccos(0.3169643)\\C=71.52^o

4 0
3 years ago
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