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olya-2409 [2.1K]
3 years ago
15

Which greatest integer function matches the graph?

Mathematics
2 answers:
kozerog [31]3 years ago
7 0

Answer:

f ( x ) = [ x ] + 1

Step-by-step explanation:

lions [1.4K]3 years ago
5 0
B would be youre answer!
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Hey please answer the 3 questions attached, thank you very much!
kobusy [5.1K]

Answer:

a) negative correlation b) Diagram C (I think) c) Diagram b

Step-by-step explanation:

a) Negative= line going dow

Positive= line going up

no correlation= no line

b) the dots are to close to each other which mean it has a string correlation.

c)Its no correlation, so line should not be drawn

7 0
3 years ago
What is the solution?
zysi [14]
The answer is point G assuming the increments are one unit.
8 0
4 years ago
Read 2 more answers
20 Points:
belka [17]

Answer:

D. 105 students and 150 guests

Step-by-step explanation:

105 students and $1 for each ticket is $105.(105 x 1 = 105)

150 guests and $5 for each ticket is $750.(150 x 5 =750)

$105 + $750 = $855

6 0
3 years ago
Read 2 more answers
Fine won't help me since I wrote long then here is short blah blah blah.......HELP ME BIT CONFUSED
Paul [167]
7/1×1/9

7×1=7
1×9=9

your answer is 7/9

hope this helped

4 0
3 years ago
Read 2 more answers
Edit: I figured it out, it's 14+7(sqrt sign) 2
Anettt [7]

Answer:

Perimeter = 14 + 7\sqrt{2}

Step-by-step explanation:

Given:

Area of the square = 49 in²

Required

Determine the perimeter of the one of the congruent triangles

First, we'll determine the length of the square;

Area = Length * Length

Substitute 49 for Area

49 = Length * Length

49 = Length^2

Take Square root of both sides

7 = Length

Length = 7

<em>When the square is divided into two equal triangles through the diameter;</em>

<em>2 sides of the square remains and the diagonal of the square forms the hypotenuse of the triangle;</em>

Calculating the diagonal, we have;

Hypotenuse^2 = Length^2 + Length^2 -- Pythagoras Theorem

Hypotenuse^2 = 7^2 + 7^2

Hypotenuse^2 = 2(7^2)

Take square root of both sides

Hypotenuse = \sqrt{2} * \sqrt{7^2}

Hypotenuse = \sqrt{2} * 7

Hypotenuse = 7\sqrt{2}

The perimeter of one of the triangles is the sum of the 2 Lengths and the Hypotenuse

Perimeter = Length + Length + Hypotenuse

Perimeter = 7 + 7 + 7\sqrt{2}

Perimeter = 14 + 7\sqrt{2}

7 0
4 years ago
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