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Dmitriy789 [7]
3 years ago
8

Help someone please hurry!

Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0
The median is going to be 75 since it is in the middle of the box.
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The distance from the center of an archery target to the outside edge of the target is 24 in. What is the diameter of the target
klemol [59]

Answer:

The diameter of the target is 48\ in

Step-by-step explanation:

we know that

In this problem the  distance from the center of an archery target to the outside edge of the target is equal to the radius of the target

so

r=24\ in

Remember that

The diameter is two times the radius

D=2r

substitute

D=2(24)=48\ in

7 0
3 years ago
Please help with problems 2-6
Airida [17]

Answer:

3. 20/20

4. 45/21

5. 7/14

6. 3 to 1

I hope this helps!

4 0
3 years ago
Find the exact volume of each cylinder
deff fn [24]
I need a picture of the cylinders to anwser your question.
7 0
3 years ago
Which of the quadratic functions has the widest graph? y = 0.3x2 y = –4x2
Alenkinab [10]
A vertical stretching is the stretching of the graph away from the x-axis.
A vertical compression is the squeezing of the graph towards the x-axis.
A compression is a stretch by a factor less than 1.

For the parent function y = f(x), the vertical stretching or compression of the function is a f(x). 

If | a | < 1 (a fraction between 0 and 1), then the graph is compressed vertically by a factor of a units.
If | a | > 1, then the graph is stretched vertically by a factor of a units.

For values of a that are negative, then the vertical compression or vertical stretching of the graph is followed by a reflection across the x-axis.

Thus, the equation with the widest graph is 0.3x^2.
4 0
3 years ago
Read 2 more answers
consider this quadratic equation x2+2x+7=21 the nuber of positive solutions to this equation are blank. the approximate value of
S_A_V [24]

Answer:

<em><u>x²</u></em><em><u>+</u></em><em><u>2</u></em><em><u>x</u></em><em><u>+</u></em><em><u>7</u></em><em><u>-</u></em><em><u>2</u></em><em><u>1</u></em><em><u>=</u></em><em><u>0</u></em>

<em><u> </u></em><em><u> </u></em><em><u>x²</u></em><em><u>+</u></em><em><u>2</u></em><em><u>x</u></em><em><u>-</u></em><em><u>1</u></em><em><u>4</u></em><em><u>. </u></em><em><u> </u></em><em><u>=</u></em><em><u>0</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>x²</u></em><em><u>+</u></em><em><u>2</u></em><em><u>x</u></em><em><u>. </u></em><em><u> </u></em><em><u>=</u></em><em><u>1</u></em><em><u>4</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>x²</u></em><em><u>+</u></em><em><u>2</u></em><em><u>x</u></em><em><u>+</u></em><em><u>1</u></em><em><u>. </u></em><em><u> </u></em><em><u>=</u></em><em><u>1</u></em><em><u>4</u></em><em><u>+</u></em><em><u>1</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>(</u></em><em><u>X+</u></em><em><u>1</u></em><em><u>)</u></em><em><u>²</u></em><em><u>. </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>=</u></em><em><u>1</u></em><em><u>5</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>X+</u></em><em><u>1</u></em><em><u>. </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>=</u></em><em><u>+</u></em><em><u>/</u></em><em><u>-</u></em><em><u>√</u></em><em><u>1</u></em><em><u>5</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>X=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>+</u></em><em><u>/</u></em><em><u>-</u></em><em><u>√</u></em><em><u>1</u></em><em><u>5</u></em>

<em><u>X=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>+</u></em><em><u>3.872983346207</u></em>

<em><u> </u></em><em><u> </u></em><em><u>=</u></em><em><u>2.872983346207</u></em><em><u>(</u></em><em><u>greate</u></em><em><u>st</u></em><em><u> </u></em><em><u>sol</u></em><em><u>ution</u></em><em><u>)</u></em><em><u> round</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>possible</u></em>

<em><u>X=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>-</u></em><em><u>3.872983346207</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>=</u></em><em><u>-</u></em><em><u>4.872983346207</u></em>

6 0
3 years ago
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