Let
be the number of hours worked at Job A and
the number of hours at Job B. Then

and

From the first equation,

and substituting this into the second gives



The answer is the last option: The associative property of multiplication
Answer:

Step-by-step explanation:
Let be
, this expression is simplified by algebraic and trascendental means. As first step, the second order polynomial is simplified. Its roots are determined by the Quadratic Formula, that is to say:


The polynomial in factorized form is:

The function can be rewritten and simplified as follows:
![f(x,y) = \log_{4} [(x-5-\sqrt{25-6\cdot y})\cdot (x-5+\sqrt{25-6\cdot y})]](https://tex.z-dn.net/?f=f%28x%2Cy%29%20%3D%20%5Clog_%7B4%7D%20%5B%28x-5-%5Csqrt%7B25-6%5Ccdot%20y%7D%29%5Ccdot%20%28x-5%2B%5Csqrt%7B25-6%5Ccdot%20y%7D%29%5D)

Answer:
mean= 8.8
median= 9
mode= 9
range= 10
ANSWER: A
Step-by-step explanation:
So dad is represented by x
son is represented by y
so x is (x=) 7 times his son (7y)
our first sentence is x=7y
10 years later (x+10, y+10) he will be 3 times as old as his son (x+10=3(y+10))
or 10+x=3(y+10)
so our sentences are
x=7y
and
x+10=3(y+10)
first we subsitute x=7y for x in the second equation
(7y)+10=3(y+10)
7y+10=3(y+10)
we distribute
7y+10=3y+30
subtract 3y from both sides
4y+10=30
subtract 10 from both sides
4y=20
divide both sides by 4
y=5
the son is currently 5 years old
x=7y
subsitute y=5 for y in equation
x=7(5)
x=35
the dad is currently 35 years old
in 10 years
dad is 45 and son is 15
dad=35
son=5