We Know that
For a function to have an inverse function, it must be one-to-one—that
is, it must pass the Horizontal Line Test.
1. On the interval [–pi/2, pi/2], the function
y = sin x is
increasing
2. On the interval [–pi/2, pi/2], y = sin x takes on its full
range of values, [–1, 1]
3. On the interval [–pi/2, pi/2], y = sin x is
one-to-one
sin x has an inverse function
on this interval [–pi/2, pi/2]
On the restricted domain [–pi/2, pi/2] y = sin x has a
unique inverse function called the inverse sine function. <span>f(x) = sin−1(x)
</span>the range of y=sin x in the domain [–pi/2, pi/2] is [-1,1]
the range of y=sin-1 x in the domain [-1,1] is [–pi/2, pi/2]
1. On the interval [0, pi], the function y = cos x is decreasing
2. On the interval [0, pi], y = cos x takes on its full range of values, [–1, 1]
3. On the interval [0, pi], y = cos x is one-to-one
cos x has an inverse function on this interval [0, pi]
On the restricted domain [0, pi] y = cos x has a unique inverse function called the inverse sine function. f(x) = cos−1(x)
the range of y=cos x in the domain [0, pi] is [-1,1]
the range of y=cos-1 x in the domain [-1,1] is [0, pi]
the answer is
<span>the values of the range are different because the domain in which the inverse function exists are different</span>
1) given
2) alternated exterior angles
3) alternated interior angles
4) transversals property
400150000 is the answer pal
<span />
Speed = Distance / Time
Distance = 5t^4 - 10t^2+6
Time = t+2
Now:
5t^4 - 10t^2 + 6 | t+2
-5t^4 -10t^3 5t^3 - 10t^2 + 10t - 20
\\\\\ -10t^3-10t^2+6
+10t^3+20t^2
\\\\\\\ 10t^2+6
-10t^2-20t
\\\\\ -20t+6
+20t+40
\\\\\ 46
<span>C. 5t^3-10t^2+10t-20+(46)/(t+2))</span>
