The area of sector is 1.57 m²
<u>Explanation:</u>
Given:
Radius, r = 3 m
Central angle of a sector = 1/9π radians
Area of sector, A = ?
We know:
Area of sector, A = 
where,
α is the central angle in radians
On substituting the value we get:
Therefore, the area of sector is 1.57 m²
Answer:
1.) 0.948
2.)0.06
3.)8.45
4.).00024
5.)0.03678
6.)2.5
Hope this helps you some!!
9514 1404 393
Answer:
Step-by-step explanation:
Let x and y represent the weights of the large and small boxes, respectively. The problem statement gives rise to the system of equations ...
x + y = 85 . . . . . combined weight of a large and small box
70x +50y = 5350 . . . . combined weight of 70 large and 50 small boxes
We can subtract 50 times the first equation from the second to find the weight of a large box.
(70x +50y) -50(x +y) = (5350) -50(85)
20x = 1100 . . . . simplify
x = 55 . . . . . . . divide by 20
Using this in the first equation, we can find the weight of a small box.
55 +y = 85
y = 30 . . . . . . . subtract 55
A large box weighs 55 pounds; a small box weighs 30 pounds.
If it is a triangle h is height and b is base.
Answer:
(9, 0)
Step-by-step explanation:
Maximum or minimum value occurs at the Corner. The points given are (0, 8), (5, 4) and (9, 0).
Substitute (0, 8) in the objective function.
We get P = 3(0) + 2(8) = 16
Now for (x , y) = (5, 4)
P = 3(5) + 2(4) = 15 + 8 = 23
At (9, 0) we get P = 3(9) + 2(0) = 27.
Clearly, we have the maximum value at (9, 0).
And the maximum value is 27.
