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sladkih [1.3K]
2 years ago
14

Geometry HELP!! MO bisects

Mathematics
1 answer:
Digiron [165]2 years ago
6 0
Since this is an angle bisector LMO is congruent to NMO

7x - 27 = 2x + 33
Subtract 2x
5x - 27 = 33
Add 27
5x = 60
Divide by 5
x = 12

Since it is asking for LMN plug in x to LMO and NMO equations

LMO:
7(12) - 27 = 57

NMO:
2(12) + 33 = 57

LMN:
57° + 57° = 114

So angle LMN is 114°
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-BARSIC- [3]

Answer:

Option B

Step-by-step explanation:

First make x = 4 and y = 3 in the equation y = -1/2x + 5

it should look like 3 = -1/2(4) + 5 now we can solve

   -1/2 * 4 = -2         →      3 = -2 +5

       -2 + 5 = 3         →          3 = 3

5 0
3 years ago
How do you add a decimal
fiasKO [112]
When adding decimals always line them up 
for example:    5.23
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see simple hope I helped

7 0
3 years ago
Read 2 more answers
Every week, Judy goes to the supermarket and buys the following: $5$ carrots at $\$1$ each, $3$ bottles of milk at $\$3$ each, $
Flauer [41]

Answer:

She spends $30 in total.

Step-by-step explanation:

Suppose that you buy X units of a given product with a price Y, then the total cost here is X*Y, with this we can solve our problem:

Every week Judy buys:

5 carrots, at $1 each, so she spends 5*$1 = $5 in carrots.

3 bottles of milk at $3, so she spends 3*$3 = $9 in milk bottles.

2 pineapples at $4 each (but the pineapples are at half price, so this week the pineapples cost $4/2 = $2), so she spends 2*$2 = $4 in pineapples.

2 bags of flour at $5 each, so she spends 2*$5 = $10 in flour.

1 giant container of ice cream, she spends $7 on it.

So the total money that she speends is:

$5 + $9 + $4 + $10 + $7 = $35

And she has a coupon for $5 in any order equal to or larger than $25, his order is larger than $25, so she can use the coupon.

So she will spend a total of $35 - $5 = $30

She spends $30 in total.

3 0
3 years ago
Convert solar days into minutes​
Pepsi [2]

Answer:

1 Solar day = 86,400 seconds (SI Base Unit)

1 day = 1,440 minutes

Step-by-step explanation:

If need anymore help just ask I'm not really good at explaining but I'll try just comment haha ☺️

6 0
3 years ago
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
3 years ago
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