point (6, -5) => x = 6, y = -5
r =√6² +(-5)² = √(36+25)=√61
the exact value of :
cos 0 = x/r = 6/√61 = 6/61 √61
csc 0 = r/y = √61/(-5) = -1/5 √61
tan 0 = y/x = -5/6
Answer:
1. Positive, 1+2=3
2. Negative, -1-2=-3
Step-by-step explanation:
If you look at both in a graphing perspective, the point (1,2) is in Quadrant I. likewise, adding 2 to the x-coordinate will also result in the point (3,2), also in Quadrant I, where the x coordinate is positive. The point (-1,2) is in Quadrant II, and adding -2 to the x coordinate keeps it in Quadrant II, where the x-coordinate is negative.
This cannot be factored or factored by grouping.
Answer:
<em><u>4(10+9) - 40 + 36</u></em>
<em><u>9(5+2) - 45 + 18</u></em>
<em><u>3(12+7) - 36 + 21</u></em>
