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scoray [572]
3 years ago
5

Clara is growing her hair out and wants it to be no longer than 15 cm but more than 11 cm. Her hair is 7 cm right now and grows

at a rate of 0.25 cm per week. Let t be the time in weeks. Which compound inequality models the scenario? 0.25 + 7t > 11 or 0.25 + 7t ≤ 15 7 + 0.25t ≥ 11 or 7 + 0.25t < 15 11 ≤ 0.25 + 7t < 15 11 < 7 + 0.25t ≤ 15
Mathematics
1 answer:
Agata [3.3K]3 years ago
8 0

Answer:

Last option

Step-by-step explanation:

After t weeks, Clara's hair will be 7 + 0.25t cm long. "No longer than" means that we use the symbol ≤ and "more than" means that we use the symbol >, hence, the answer is 11 < 7 + 0.25t ≤ 15.

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Which expressions show the prime factorization of 90?
Andreas93 [3]
Prime factorization means that we divide 90 by prime numbers only.

90 ÷ 2 = 45
45 ÷ 3 = 15
15 ÷ 3 =   5

2 x 3 x 3 x 5 = 90

2 x 3² x 5 = 90 
or 2,3,3,or 5

7 0
3 years ago
Write an equation of the line that passes through the given points.<br> question (-4, 3), (O, -10)
expeople1 [14]

Answer:

Y=(\frac{4}{7}) x+2

Step-by-step explanation:

Y=mx+b

M=\frac{x2-x1}{y2-y1}

M=\frac{0-(-4)}{-10-3}

M=\frac{-4}{-7}

Y=(\frac{4}{7}) x+2

3 0
3 years ago
2y+3x=90 what is x and y
yan [13]

If x=-6 then y=54.
If x=-4 then y=51.
If x=-2 then y=48.
If x=0 then y=45.
If x=2 then y=42.
If x=4 then y=39.
If x=6 then y=36.

There are an infinite variety of pairs of numbers for 'x' and 'y'
that can make that equation true.

You can use that equation to draw a  line on a graph.  Then
EVERY point on the line is a solution to the equation.

'x' and 'y' don't have single values unless you have TWO equations.

4 0
3 years ago
The Venn diagram shows the results of two events resulting from rolling a number cube.
gulaghasi [49]

Answer:   P(A\cap B)=\frac{1}{3}

P(A)=\frac{1}{3}

P(B)=1

P(A|B)=\frac{1}{3}

Step-by-step explanation:

From the given figure it can be seen that

Total number on cube= n(S)=6

Intersection of A and B = n(A ∩ B)= 2

Therefore,

P(A\cap B)=\frac{n(A\cap B)}{n(s)}=\frac{2}{6}=\frac{1}{3}

Also, The number of elements in A = 2

Therefore,

P(A)=\frac{n(A)}{n(s)}=\frac{2}{6}=\frac{1}{3}

Similarly, The number of elements in B= 6

Therefore,

P(B)=\frac{n(B)}{n(s)}=\frac{6}{6}=1

The formula to find the conditional probability is given by :-

P(A|B)=\frac{P(A\cap B)}{P(B)}\\\\\Rightarrow P(A|B)=\frac{\frac{1}{3}}{1}=\frac{1}{3}

4 0
4 years ago
Read 2 more answers
Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b
jeka94

Answer:

Step-by-step explanation:

From the given information; Let's assume that  R should represent the set of all possible outcomes generated from  a bit string of length 10 .

So; as each place is fitted with either 0 or 1

\mathbf{|R|= 2^{10}}

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

Now;

if  a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

\mathbf{P(E) = \dfrac{|E|}{|R|}}

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:

\mathbf{{|E|}=1 }   ; \mathbf{|R|= 2^{10}}

\mathbf{P(E) = \dfrac{1}{2^{10}}}

4 0
3 years ago
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