For Data Set B, we see that the data is more varied. The absolute deviations are 4, 3, 2, 5. The average of these absolute deviations is 3.5. MAD_B = (4+3+2+5)/4 =3.5 M ADB
Hence, The average of these absolute deviations is 3.5.
ANSWER
y = 2/3x + 15
Explanation:
Equation used: y - y1 = m( x - x1 )
y - 9 = 2/3 ( x - -9 )
y - 9 = 2/3x + 6 ( distribution )
y - 9 = 2/3x + 6 ( add 9 to 6 )
y = 2/3x + 15
Answer:
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