-13 is half way between -46 and 20
This is a probability problem with two dependent events and conditional probability. Note that after the first donut is chosen, it is not replaced into the data set, so only 23 donuts remain. If we set A=selection of a lemon-filled, and B=selection of a custard-filled, then P(A and B) = P(A)*P(B|A), where P(B|A) means the probability of B happening given that A has already occurred.P(A) = 8/24 = 1/3 = 0.333333P(B|A) = 12/23 = 0.521739P(A and B) = 1/3(12/23) = 12/69 = 0.1739130435 or 17.4%
https://www.wyzant.com/resources/answers/296921/find_the_probability_of_selecting_a_a_lemon_filled_d...
The cost of other seats £40 and £24.
<h3>What is ratio?</h3>
A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.
Given ratio: A: B : C = 5 : 3 :2
let the common ratio be 'x'.
Grade A cost = 5x
Grade B cost = 3x
Grade C cost = 2x
cheapest seats the concert £16
So,
2x=16
x=8
Now, Grade A cost = 5x = 5*8 = £40
Grade B cost = 3x= 3*8 = £24.
Learn more about ratio here:
brainly.com/question/13419413
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Answer:
Probability = 0.58
Step-by-step explanation:
This problem is solve by using Baye's Probability.
Let P(A) = Probability that operator attended training course = 50% = 0.5
P(B) = Probability that operator not attended training course = 50% = 0.5
Also P(Q) = Probability that operator meet their production quotas
Then, P(Q|A) = 90% = 0.9
P(Q|B) = 65% = 0.65
P(A|Q) = ?
Then by Baye's Theorem,
⇒ 
⇒ P(A|Q) = 0.58
which is required probability.
U didn't mess up....
V = pi * r^2 * h....divide both sides by (pi)r^2
V / (pi)r^2 = h
