Question

Find the exact value of sec 330° in simplest form with a rational denominator.

Answer 1

Answer:

$\implies \sec 330^o = \dfrac{2}{\sqrt3}=\dfrac{2\sqrt{3}}{3}$

Step-by-step explanation:

Given :-

• $\sec 330^o$

And we need to find out its value . Firstly we know that 330° lies in 4th quadrant . And In fourth quadrant , cosine and secant are positive . Therefore , the result will be positive. Now we know that ,

$\implies \sec (360^o-\theta)= \sec\theta$

Using this ,

$\implies \sec (330^o) \\\\\rm\implies sec(360^o-30^o) \\\\\rm\implies \sec 30^o$

And the value of sec 30° is ,

$\implies \sec 30^o = \dfrac{2}{\sqrt3}$

And by question we need to write it with a rational denominator .So on rationalising the denominator , we have ,

$\implies \sec 30^o = \dfrac{2}{\sqrt3}=\boxed{\red{\dfrac{2\sqrt3}{3}}}$

Hence the required answer is 2√3/3.

Answer 2

Answer:

2√3/3

Step-by-step explanation:

Sec(330°)

=1/cos(330°)

=1/√3/2 (since Cos (330°)=√3/2

=1×2/√3

=2/√3×√3/√3

=2√3/3