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3 years ago

Please answer the one u can do

Mathematics

2 answers:

Ber [7]3 years ago

4 0

6. B.... (6,2)
hope this helps and HAGD!!!

Charra [1.4K]3 years ago

3 0

I believe #7 is D) 5.5 x W

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When the absolute value of the slope gets bigger, the graph of a line gets _____.

Kruka [31]

Longer B is the right answer

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2 years ago

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Which of the following equations represents a line that is parallel to the line 3x - 2y = 12

sveticcg [70]

Answer:

Step-by-step explanation:

12=3x-2y

2y+12=3x

2y=3x-12

y=(3x-12)/2

y=mx+b

To be parallel to the line above our line must have the same slope or m. The above line has a slope of 3/2 or 1.5 so the parallel line will be

y=1.5x+b, using point (7,10) we can solve for the y intercept or b

10=1.5(7)+b

10=10.5+b

b=-0.5 so our line is

y=1.5x-0.5

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2 years ago

Solve for the missing item in the following. (Do not round intermediate calculations. Round your answer to the nearest cent.)

iogann1982 [59]

9514 1404 393

Answer:

$1904.76

Step-by-step explanation:

The interest formula is ...

I = Prt . . . . interest on principal P at rate r for t years

Solving for P, we find ...

P = I/(rt) = 200/(0.07·1.5) = 200/0.105 ≈ 1904.76

The principal amount was $1904.76.

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2 years ago

One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p

scZoUnD [109]

Answer:

$c^2 = 9dp$

Step-by-step explanation:

Given

$dx^2 + cx + p = 0$

Let the roots be $\alpha$ and $\beta$

So:

$\alpha = 2\beta$

Required

Determine the relationship between d, c and p

$dx^2 + cx + p = 0$

Divide through by d

$\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0$

$x^2 + \frac{c}{d}x + \frac{p}{d} = 0$

A quadratic equation has the form:

$x^2 - (\alpha + \beta)x + \alpha \beta = 0$

So:

$x^2 - (2\beta+ \beta)x + \beta*\beta = 0$

$x^2 - (3\beta)x + \beta^2 = 0$

So, we have:

$\frac{c}{d} = -3\beta$ -- (1)

and

$\frac{p}{d} = \beta^2$ -- (2)

Make $\beta$ the subject in (1)

$\frac{c}{d} = -3\beta$

$\beta = -\frac{c}{3d}$

Substitute $\beta = -\frac{c}{3d}$ in (2)

$\frac{p}{d} = (-\frac{c}{3d})^2$

$\frac{p}{d} = \frac{c^2}{9d^2}$

Multiply both sides by d

$d * \frac{p}{d} = \frac{c^2}{9d^2}*d$

$p = \frac{c^2}{9d}$

Cross Multiply

$9dp = c^2$

$c^2 = 9dp$

Hence, the relationship between d, c and p is: $c^2 = 9dp$

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2 years ago

A direct variation function contains the points (2, 14) and (4, 28). Which equation represents the function?

IgorC [24]

Direct variation mean x =ky so y = x/k

(2,14) mean y = kx so 14 = k*2 so 14 = 7*2 so 14 = 14
(4,28) mean y = kx so 28 = k*4 so 28 = 7*4 so 28 = 28

from these result that the 3rd choice is right sure

6 0

2 years ago

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