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MAXImum [283]
3 years ago
13

Q

Mathematics
1 answer:
Tema [17]3 years ago
4 0

Answer:

y = \frac{1}{2} x+7

Step-by-step explanation:

Slope-intercept form: y = mx + b

Slope formula: \frac{y2-y1}{x2-x1}

Given points: (-6, 4), (6, 10)

(-6, 4) = (x1, y1)

(6, 10) = (x2, y2)

To write the equation in slope-intercept form, we need to find the slope(m) and the y-intercept(b) of the equation.

First, let's find the slope. To do this, input the given points into the slope formula:

\frac{10-4}{6-(-6)}

Simplify:

10 - 4 = 6

6 - (-6) = 6 + 6 = 12

\frac{6}{12}=\frac{1}{2}

The slope is \frac{1}{2}.

To find the y-intercept, input the slope and one of the given points(in this example I'll use point (6, 10)) into the equation and solve for b:

10 = \frac{1}{2}(6)+b

10 = 3 + b

7 = b

The y-intercept is 7.

Now that we know the slope and the y-intercept, we can write the equation:

y = \frac{1}{2} x+7

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Step-by-step explanation:

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Sidana [21]

Answer:

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Step-by-step explanation:

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Find the equation of the tangent line. y=(9-x^2)^1/3 at (1,2)​
Schach [20]

Get the derivative:

<em>y</em> = (9 - <em>x</em>²)¹ʹ³

d<em>y</em>/d<em>x</em> = 1/3 (9 - <em>x</em>²)⁻²ʹ³ d/d<em>x</em> [9 - <em>x</em>²]

d<em>y</em>/d<em>x</em> = 1/3 (9 - <em>x</em>²)⁻²ʹ³ (-2<em>x</em>)

d<em>y</em>/d<em>x</em> = -2/3 <em>x</em> (9 - <em>x</em>²)⁻²ʹ³

Evaluate it at <em>x</em> = 1 :

d<em>y</em>/d<em>x</em> (1) = -2/3 • 8⁻²ʹ³

Since 8 = 2³, we have

8⁻²ʹ³ = 1 / 8²ʹ³ = 1 / (2³)²ʹ³ = 1 / 2² = 1/4

Then the tangent line has equation

<em>y</em> - 2 = 1/4 (<em>x</em> - 1)   →   <em>y</em> = 1/4 <em>x</em> + 7/4

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3 years ago
The square pqrs is shown.
ira [324]

Answer:

1:1

Step-by-step explanation:

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3 years ago
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