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MAXImum [283]
3 years ago
13

Q

Mathematics
1 answer:
Tema [17]3 years ago
4 0

Answer:

y = \frac{1}{2} x+7

Step-by-step explanation:

Slope-intercept form: y = mx + b

Slope formula: \frac{y2-y1}{x2-x1}

Given points: (-6, 4), (6, 10)

(-6, 4) = (x1, y1)

(6, 10) = (x2, y2)

To write the equation in slope-intercept form, we need to find the slope(m) and the y-intercept(b) of the equation.

First, let's find the slope. To do this, input the given points into the slope formula:

\frac{10-4}{6-(-6)}

Simplify:

10 - 4 = 6

6 - (-6) = 6 + 6 = 12

\frac{6}{12}=\frac{1}{2}

The slope is \frac{1}{2}.

To find the y-intercept, input the slope and one of the given points(in this example I'll use point (6, 10)) into the equation and solve for b:

10 = \frac{1}{2}(6)+b

10 = 3 + b

7 = b

The y-intercept is 7.

Now that we know the slope and the y-intercept, we can write the equation:

y = \frac{1}{2} x+7

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(x - 6)(x + 2) = 0
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x -  6 = 0; x = 6
x + 2 = 0; x = -2

answer
x = -2 or x = 6</span>
8 0
3 years ago
Read 2 more answers
In a right triangle, the measure of one acute angle is 26°. What is the measure of the other acute angle?
Makovka662 [10]
The sum of the angles of a triangle ALWAYS sum up to 180 degrees.  So to find the other angle, you would take 180, subtract 90, and then subtract 26, to get 64.
The measure of the 3rd angle equals 64.
5 0
3 years ago
I need help with this!!
tresset_1 [31]

Answer:

you would use 85 to find angle 4, because they would add up to 180, so you would subract 85 from 180 to get angle 4

Step-by-step explanation:

5 0
3 years ago
I already solved this problem. I just need help with the HINT part.
frutty [35]
x+y=25 \\ y=25-x~~Other~number~in~terms~of~x \\ \\ x^2+y^2=313 \\ x^2+2xy+y^2=313+2xy \\ (x+y)^2=313+2x(25-x) \\ \frac{25^2-313}{2} =25x-x^2 \\ x^2-25x+156 \\ \\ \Delta =(-25)^2-4\times 1\times 156 \\ \Delta =625-624 \\ \sqrt{\Delta}=1 \\ \\ x= \frac{25 \pm 1}{2} \\ x= \left \{ {{x_1=13} \atop {x_2=12}} \right.

     The number "x" is given by:
y= \left \{ {{y_1=25-13 \rightarrow~y_1=12} \atop {y_1=25-12 \rightarrow ~y_1=13}} \right.
  
     Therefore, we have:

\boxed {S=({12,13})} \rightarrow~The~curly~braces~does~not~want~appear~here.
8 0
3 years ago
Help with #9 linked above! Please help!
jasenka [17]

y = A(Bx - C)ⁿ + D

A is a vertical stretch (or shrink if |A| < 1)

B is a vertical shrink (or stretch if |B| < 1)

C is a shift to the right (or left if C is negative) → notice that Bx - C is "-C" so to take the opposite

D is a shift up (or down if D is negative)

when C = -3, it is a shift to the left 3 units

when D = -7, it is a shift down 7 units

Answer: B

6 0
3 years ago
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