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serious [3.7K]
3 years ago
8

HELP PLEASE BRAINIEST IF CORRECT!!!! Function or not function.

Mathematics
2 answers:
lutik1710 [3]3 years ago
7 0

Answer:

Function

Step-by-step explanation:

If you can draw a vertical line and it does not intercept twice it is a function

Tom [10]3 years ago
5 0

Answer:

It is a function

Step-by-step explanation:

The line doesn't pass through the graph twice

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Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
Andre45 [30]

For this case, we must indicate which of the given functions is not defined forx = 0

By definition, we know that:

f (x) = \sqrt {x} has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative when x = 0.

While y = \sqrt {x + 2} if it is defined for x = 0.

f(x)=\sqrt[3]{x}, your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

y = \sqrt [3] {x-2} with x = 0: y = \sqrt [3] {- 2} is defined.

y = \sqrt [3] {x + 2}with x = 0: y = \sqrt [3] {2}in the same way is defined.

Answer:

y = \sqrt {x-2}

Option b


6 0
3 years ago
Help please thank you.
Shkiper50 [21]
3 \sqrt{5} + 6 \sqrt{9} \sqrt{5}
3 \sqrt{5}+6 \sqrt{45}
3 \sqrt{5}+6*3 \sqrt{5}
3 \sqrt{5} + 18 \sqrt{5}  = 21 \sqrt{5}
5 0
3 years ago
If a = 4 and b = 7, what is the value of the following expression? 20 ÷ a + 7 • b A. 28 B. 84 C. 54 D. 33
expeople1 [14]

Answer:

54

Step-by-step explanation:

20 ÷ a + 7 • b

Let a = 4 and b = 7

20 ÷ 4 + 7 • 7

Multiply and divide first

5 + 49

Then add

54

8 0
3 years ago
Read 2 more answers
Which function does not have an asymptote ?
kozerog [31]

Answer:

y=\cos(x)

Step-by-step explanation:

The function y=secx=\frac{1}{cosx}.

There is a vertical asymptote at cosx=0

The function y=cotx=\frac{cosx}{sinx}.

There is a vertical asymptote at sinx=0

The function y=cscx=\frac{1}{sinx}.

There is a vertical asymptote at sinx=0

The function y=cosx.

has no asymptote

3 0
3 years ago
Answer in simplest fractional form. negative 1 fifth + negative 3 fourths =
kramer
-1/5 + (-3/4)
= -1/5 - 3/4
= -4/20 - 15/20
= -19/20
5 0
3 years ago
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