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2 years ago

Translate this phrase into an algebraic expression.

Mathematics

1 answer:

lara31 [8.8K]2 years ago

7 0

Answer:

7+2g

Step-by-step explanation:

7 increased by means 7 +

twice Gali's height =2g

everything now becomes 7+2g

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Solve for x, rounding to the nearest hundredth. 10^3x = 98

Anna71 [15]

Answer:

see explanation

Step-by-step explanation:

10^3x=98

1000x=98

x=98/1000

x=49/500

x=0.98

if it is rounded to the nearest hundredth then x=0

8 0

3 years ago

WILL MARK U BRAINLIEST PLEASE HELP

natulia [17]

The height of the cone is 8.59

6 0

3 years ago

Read 2 more answers

6. A surveyor walks the perimeter of a piece of government land. He notes that the area of the land

Vlada [557]

Answer:

A) l = w + 900

B) l * w = 4,000,000

B) l = 4,000,000 / w putting this into A)

A) 4,000,000 / w = w + 900

A) 4,000,000 = w^2 +900 w

A) w^2 +900 w - 4,000,000

Solving by quadratic formula

width = 1,600 length = 2,500

Double-Check

1,600 * 2,500 = 4,000,000

Length = width + 900

2,500 = 1,600 + 900

Answer is okay

Step-by-step explanation:

8 0

3 years ago

Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len

Rama09 [41]

The length of a curve C parameterized by a vector function r(t) = x(t) i + y(t) j over an interval a ≤ t ≤ b is

$\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt$

In this case, we have

x(t) = exp(t ) + exp(-t ) ==> dx/dt = exp(t ) - exp(-t )

y(t) = 5 - 2t ==> dy/dt = -2

and [a, b] = [0, 2]. The length of the curve is then

$\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt$

$=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt$

$=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt$

$=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt$

$=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}$

5 0

3 years ago

In 1980, James planted a tree that was 1 foot tall. In 1996, that same tree was 51 feet tall. James finds that the height of the

Rashid [163]

Divide and see what you get = 51

7 0

3 years ago