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3 years ago

7

What is the solution to this equation? 7- 3√2-x=12

2 answers:

dedylja [7]3 years ago

4 0

Answer:

x=-5-3 $\sqrt{2}$

It cannot be more simplified.

pantera1 [17]3 years ago

4 0

7-3/14-x

Solution:
7-3/2-x=12

7-3/14-x

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(MIDDLE SCHOOL MATH) please help!

finlep [7]

52 x 1.05 = $54.60
+ $4.37 (taxes) = $58.97
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3 years ago

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Whoever does it first will get a brainiest

Gnom [1K]

Answer:

same

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Step-by-step explanation:

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2 years ago

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nasty-shy [4]

I think proving a more general form will actually be easier than this specific case - it appears to be true that

$2^{n+1}\cot(2^{n+1}\alpha)+\displaystyle\sum_{i=0}^n2^i\tan(2^i\alpha)=\cot\alpha$

for $n=0,1,2,3,\ldots$ .

Let's consider a proof by induction. The base case $n=0$ gives

$2\cot2\alpha+\tan\alpha=2\dfrac{\cos2\alpha}{\sin2\alpha}+\dfrac{\sin\alpha}{\cos\alpha}$

$=\dfrac{\cos^2\alpha-\sin^2\alpha}{\sin\alpha\cos\alpha}+\dfrac{\sin\alpha}{\cos\alpha}$

$=\dfrac{\cos^2\alpha-\sin^2\alpha+\sin^2\alpha}{\sin\alpha\cos\alpha}$

$=\dfrac{\cos\alpha}{\sin\alpha}=\cot\alpha$

as desired.

Suppose the identity holds for $n=k$ , so that

$2^{k+1}\cot(2^{k+1}\alpha)+\displaystyle\sum_{i=0}^k2^i\tan(2^i\alpha)=\cot\alpha$

For $n=k+1$ , we have

$2^{k+2}\cot(2^{k+2}\alpha)+\displaystyle\sum_{i=0}^{k+1}2^i\tan(2^i\alpha)$

$=2^{k+2}\cot(2^{k+2}\alpha)+2^{k+1}\tan(2^{k+1}\alpha)+\displaystyle\sum_{i=0}^k2^i\tan(2^i\alpha)$

$=2^{k+2}\cot(2^{k+2}\alpha)+2^{k+1}\tan(2^{k+1}\alpha)+(\cot\alpha-2^{k+1}\cot(2^{k+1}\alpha))$

So we ultimately need to show that

$2^{k+2}\cot(2^{k+2}\alpha)+2^{k+1}\tan(2^{k+1}\alpha)-2^{k+1}\cot(2^{k+1}\alpha)=0$

or

$2\cot(2^{k+2}\alpha)+\tan(2^{k+1}\alpha)=\cot(2^{k+1}\alpha)$

If we replace $\beta=2^{k+1}\alpha$ , we get(!) the base case, which we've shown to be true,

$2\cot2\beta+\tan\beta=\cot\beta$

and thus the identity is proved.

4 0

4 years ago

Cuanto es 34839269693+15534345345677856336.

PtichkaEL [24]

1.5534345e+19 is what the google calculator says

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4 years ago

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4.) Katrina is reading a book that has 384 pages. If she reads 12 pages a day, how many days will it

JulsSmile [24]

384 / 12 = 32.

Long division.

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4 years ago