Find the x-component of this

An object moving north with an initial velocity of 14m/s accelerates 5m/s squared. What is the final velocity of the object?

OLEGan [10]

The final velocity of the object is 16m\s.
Hope this helps! :)

6 0

3 years ago

Studies of the relationship of the Sun to our galaxy-the Milky Way-have revealed that the Sun is located near the outer edge of

lianna [129]

Mass of the milkyway galaxy :

$M_{mw} = \frac{4\pi ^{2}r^{3}}{GT^{2}}\\\\M_{mw} = \frac{4\pi ^{2}(3x10^{4}x9.46x10^{15})^{3}}{6.67x10^{-11}Nm^{2}/Kg^{2}x(7.13x10^{15})^2}\\\\M_{mw } = 2.7x10^{14} Kg$

The magnitude of the mass of the Milky Way galaxy = $2.7x10^{14} Kg$

<h3>Can galaxies recycle stars?</h3>

Galaxies do not appear to have sufficient matter inside them to keep shaping modern stars at the rates that they do. Presently, astronomers have caught a universe within the act of reusing fabric that it already tossed out, which may clarify the discrepancy. New perceptions give the primary coordinate evidence of gas streaming into distant galaxies that are effectively making infant stars, offering support for the "galactic recycling" theory.

To learn more about galactic recycling, visit;

brainly.com/question/6272572

#SPJ4

6 0

2 years ago

СРОЧНО ПОМОГИТЕ ПОЖАЛУЙСТА!!!!!!!!!!<br>

Deffense [45]

Боже, как это сложно! Ну ладно.

Между прочим это ты сам должен делать, а то не куда не поступишь!

3 0

3 years ago

At one point in the circuit, there is an LED and a resistor in parallel with one another. If you measure the voltage drop across

kifflom [539]

Answer:

C. The voltage drop across the resistor is 2.1V and nothing about the current through the resistor.

Explanation:

When connected in parallel, voltage across the resistances are the same. So if 2.1V was dropped across the LED then 2.1V was also dropped across the resistor. However, this tells us nothing about the current through the resistor. We can find the current across the resistor if we know the resistance of the resistor, but that's about it.

If it were a series connection, then the current would have been the same, but the voltage drop were another story.

7 0

3 years ago

16 grams of ice at –32°C is to be changed to steam at 182°C. The entire process requires _____ cal. Round your answer to the nea

ICE Princess25 [194]

Answer:

12432 cal.

Explanation:

The process to change ice at -32 ºC to steam at 182 ºC can be divided into 5 steps:

1. Heat the ice to 0 ºC, which is the fusion temperature.

2. Melt the ice (obtaining liquid water), which is a process at constant pressure and temperature, so the liquid obtained is also at 0ºC.

3. Heat the liquid water from 0 ºC to 100 ºC, which is the vaporization normal temperature of the water.

4. Vaporization of all the water; this is also a process that occurs at constant pressure and temperature, so the produced steam will be at 100ºC.

5. Heat the steam from 100 ºC to 182 ºC.

Each process has a required energy, and the sum of the energy required for each and all of the steps is the total amount of energy required for the whole process:

$E_T=E_1+E_2+E_3+E_4+E_5$