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jekas [21]
3 years ago
15

What is the value of x

Mathematics
2 answers:
schepotkina [342]3 years ago
8 0

Answer:

x=2

Step-by-step explanation:

\cfrac{7}{9}\:x-\cfrac{4}{9}\:x=\cfrac{1}{4}+\cfrac{5}{12}

First, combine  \frac{7}{9} x and -\frac{4}{9} x =  \frac{1}{3} x

\cfrac{1}{3}\: x=\cfrac{1}{4} +\cfrac{5}{12}

LCM of 4 and 12 is 12, Convert 1/4 and 5/12 to fraction with denominator 12:

\cfrac{1}{3}\: x=\cfrac{3}{12} +\cfrac{5}{12}

Since 3/12 and 5/12 have the same denominator, let's add numerators:

\cfrac{1}{3}\:x=\cfrac{3+5}{12}

\cfrac{1}{3}\:x=\cfrac{8}{12}

Reduce the fraction 8/12 to lowest term by extracting and  canceling out 4,

\cfrac{1}{3} \:x=\cfrac{2}{3}

Multiply both sides by 3, reciprocal of 1/3:

x=\cfrac{2}{3} \times 3

Cancel out 3 and 3:

x=2

_________________________________

Nesterboy [21]3 years ago
7 0

Answer:

x = 2

Step-by-step explanation:

First simplify the equation.

  1. \frac{7}{9}x -\frac{4}{9} =\frac{1}{4} +\frac{5}{12}
  2. \frac{3}{9}x= \frac{3}{12} +\frac{5}{12}
  3. \frac{3}{9}x=\frac{8}{12}
  4. \frac{1}{3}x=\frac{2}{3}

Now multiply both sides by 3.

x = 2

I hope it helps you. Please choose my answer as the BRAINLIEST.

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Help me out plzz will give u brainliest
djyliett [7]

Answer: Option 3 = 4

Step-by-step explanation: f(x) = 6 - 2x

f(0) = 6 - 2(0) Range = 6

f(2) = 6 - 2(2) Range = 2

f(4) = 6 - 2(4) Range = -2

f(6) = 6 - 2(6) Range = -6

f(8) = 6 - 2(8) Range = -10

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You're welcome!!

Nighty Night!!!

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3 years ago
Read 2 more answers
Solve: 5y – 3.5 = 10.5
Svetlanka [38]

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7 0
3 years ago
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Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children
Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

p = 0.69

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}

0.07\sqrt{n} = 1.2996

\sqrt{n} = \frac{1.2996}{0.07}

\sqrt{n} = 18.5658

(\sqrt{n})^{2} = (18.5658)^{2}

n = 345

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0
3 years ago
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